Answer:
The answer to your question is below
Step-by-step explanation:
Data
Equation 25x² + 64y² = 1600
Process
1.- Divide all the equation by 1600
25x²/1600 + 64y²/ 1600 = 1600/1600
-Simplify
x²/64 + y²/ 25 = 1
2.- Equation of a horizontal ellipse

3.- Find a, b and c
a² = 64 a = 8
b² = 25 b = 5
-Calculate c with the Pythagorean theorem
a² = b² + c²
-Solve for c
c² = a² - b²
-Substitution
c² = 8² - 5²
-Simplification
c² = 64 - 25
c² = 39
-Result
c = √13
4.- Find the center
C = (0, 0)
5.- Find the vertices
V1 = (-8, 0) V2 = (8, 0)
6.- Find the foci
F1 = (-√13, 0) F2 = (√13, 0)
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Just did a specific one of these; let's do the general case.
The point nearest the origin is (a,b).
The line from the origin through the point is

The line we seek is perpendicular to this one. We swap the coefficients on x and y, negating one, to get the perpendicular family of lines. We set the constant by plugging in the point (a,b):


That's standard form; let's plug in the numbers:

