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Hitman42 [59]
2 years ago
11

Solving by Elimination

Mathematics
1 answer:
Bond [772]2 years ago
4 0

Answer:

unsolvable

Step-by-step explanation:

by elemination 14x+7y=-7 (1)

-14x-7y=7 (2)

x and y will be 0 then

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An electric company charges a certain rate per kilowatt-hour (\text{kWh})(kWh) of electricity used and an administrative fee of
zavuch27 [327]

Answer:

r represents the rate the electric company charges per kilowatt-hour.


Step-by-step explanation:

r represents the rate the electric company charges per kilowatt-hour.


Total charged to Zhao was 63.25 out of which 3.50 is administrative charge (fixed).

  • Total charge consists of "administrative charge" + "charge per kilowatt hours*hours used
  • The equation is given as 63.24 = 3.5 + 800r

<u>Matching the "word equation" with "mathematical equation", we see that 800 is the hours used and r is the charge per kilowatt hour.</u>

3 0
2 years ago
Read 2 more answers
Please help I’m so confused (picture has question)
kipiarov [429]

Answer:

C.

Step-by-step explanation:

all you do is go look and see which one is in the exact same spot


3 0
2 years ago
Read 2 more answers
Twenty-seven is<br>% of 60<br>help mee asap​
jok3333 [9.3K]

Answer:  The answer is:  " <u> </u><u>45 </u>  % "  .    

________________________________________________

               →    " Twenty-seven is <u> 45 </u> % of 60. "

________________________________________________

Step-by-step explanation:

________________________________________________

The question asks:

 " 27 is what % {percentage] of 60 " ?  ;

________________________

So:  " 27 =  (n/100) * 60 " ;  Solve for "n" ;

________________________________________________

Method 1:

________________________________________________

  →   (n/100) * 60 = 27 ;

Divide each side by 60 :

 →   [ (n/100)  * 60 ] / 60 = 27 /60 ;

to get:

 →    (n/100) = 27/60 ;

Now:  Cross-factor multiply:

 →  60n = (27)*(100) ;

to get:

 → 60n = 2700 ;

Divide each side by "60" ;

→  60n = 2700/ 60 ;

to get:  n = 45 ;

________________________

 →  The answer is:  45 % .    

   →  " Twenty-seven is <u>45 %</u> of 60."

________________________________________________

Method 2:

________________________________________________

The question asks:

 " 27 is what % {percentage] of 60 " ?

________________________

To solve this problem:

Rephrase this question as:

________________________

" 27 is 60% of what number ? "

 →  The answer will be the same!

________________________

→  27 = (60/100)* n ;   Solve for "n" ;

Multiply each side of the equation by "100" ; to eliminate the fraction:

→  100 * 27 = 100 * [ (60/100)* n ] ;

 to get:

   →   2700 = 60n ;

↔  60n = 2700 ;

Divide Each Side of the equation by "60" ;

    →   60n/60 = 2700 / 60 ;

to get:  n = 45 ;

________________________________________________

→  The answer is:  45 % .    

       →  " Twenty-seven is <u>45 %</u> of 60."

________________________________________________

Method 2:  Variant 1 of 2:

________________________________________________

When we have:

→  27 = (60/100)* n ;   Solve for "n" ;

________________________

Note that:  "(60/100) = (60÷ 100) = (6 ÷ 10)" ;   since:  in "(60/100)" ;  the "zero" from the "<u>numerator</u>" cancels out;  <u>And</u>:  the "last zero" in "100" — from the "<u>denominator</u>" cancels out;  since we are dividing "each side" of the fraction by "10" ;

  →   "(60÷10) / (600÷10)"  =  " 6/10 " ;  

  →   " (6/10)" ; that is;  "six-tenths"} ;  

  →     can be represented by:  " 0.6 " ;

  →  {by convention;  but specifically, here is the explanation} — as follows:

________________________

  →   "(6/10)" =  " (6 ÷ 10) " ;  

<u>Note</u>:  When dividing a number by "10" ;  we take the original number; and move the decimal point to the left; & then we rewrite that number as the "answer".  

<u>Note</u>:  When multiplying or dividing by a positive, non-zero integer factor of "10" that has at least 1 (one) "zero" after that particular factor of "10".  We can get the answer by taking the original number & moving the decimal point the number of spaces as designated by the number of zeros following the particular [aforementioned factor of "10".].

We move the decimal point to the right if we are multiplying;  and to the left  if we are dividing.  In this case, <u>we are dividing</u> "6" by "10 " :

 →  " 6   ÷  10  =  ? " ;  

 →  " 6.  ÷ 10 =  ? " ;

   We take the: " 6. " ;  and move the decimal point "<u>one space backward [i.e. "to the left</u>"];  since we are <u>dividing by "</u><u>10</u><u>"</u> ;

 →  to get:  " .6 " ;  & we rewrite this value as "0.6" in a rewritten equation:

________________________

So; we take our equation:

→  27 = (60/100)*n ;  And rewrite—substituting "0.6" for

"(60/100)"— as follows:

________________________

→  27 = (0.6)n ;  ↔ (0.6) n = 27 ;

Multiply each side of the equation by "10" ; to eliminate the decimal:

   →  10 * [ (0.6)n ]  = 27 * 10 ;

to get:

  →  6n = 270 ;

Divide each side of the equation by "6" ; to isolate "n" on one side of the equation; & to solve for "n" ;

 →  6n / 6  =  270 / 6 ;

to get:   n = 45 ;

________________________________________________

→  The answer is:  45 % .    

      →  " Twenty-seven is <u>45 %</u> of 60."

________________________________________________

Method 2 (variant 2 of 2):

________________________________________________

We have the equation:  27 = (60/100)* n ;   Solve for "n" ;

________________________

<u>Note</u>:  From Method 2 (variant) 1 of 2— see above):

________________________

<u>Note</u>:  Refer to the point at which we have:

________________________

→   " {  (60÷10) / (600÷10)"  =  " (6/10) " ;  that is;  "six-tenths"} ;

________________________

Note that the fraction— "(6/10)" ;  can be further simplified:

→  "(6/10)" =  "(6÷2) / (10÷2)" = "(3/5)" ;

Now, we can rewrite the equation;

→ We replace "(60/100)" ;  with:  "(3/5)" :

    →  27 = (3/5)* n ;   Solve for "n" ;

↔ (3/5)* n = 27 ;  

↔    (3n/5) = 27 ;

Multiply Each Side of the equation by "5" ;

→  5* (3n/5) = 27 * 5 ;  

to get:

→   3n = 135 ;

Divide Each side of the equation by "3" ;  to isolate "n" on one side of the equation;  & to solve for "n" ;

→  3n / 3 = 135 / 3  ;

to get:   n = 45 ;

________________________________________________

 →  The answer is:  45 % .    

       →  " Twenty-seven is <u>45 %</u> of 60."

________________________________________________

Hope this answer is helpful!

        Wishing you the best in your academic endeavors

           — and within the "Brainly" community!

________________________________________________

7 0
3 years ago
Read 2 more answers
Work out the total surface area of this hemisphere which has a radius of 8cm.
Masja [62]

\bf \textit{surface area of a sphere}\\\\ SA=4\pi r^2~~ \begin{cases} r=radius\\ \cline{1-1} r=8 \end{cases}\implies SA=4\pi (8)^2\implies SA=256\pi \\\\\\ \stackrel{\textit{half of that for a \underline{hemi}sphere}}{\cfrac{256\pi }{2}\implies 128\pi \implies }\stackrel{\textit{rounded up}}{402.1}

4 0
2 years ago
Please answer correctly !!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!
olya-2409 [2.1K]

Answer:

-10

Step-by-step explanation:

-(x-5) ^2+25

-x+5^2+25

-5 -5

-x^2+20

-2x+20

---- ----

-2 -2

x=-10

// have a great day //

3 0
3 years ago
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