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Hitman42 [59]
2 years ago
11

Solving by Elimination

Mathematics
1 answer:
Bond [772]2 years ago
4 0

Answer:

unsolvable

Step-by-step explanation:

by elemination 14x+7y=-7 (1)

-14x-7y=7 (2)

x and y will be 0 then

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Find the value of x: 3(6x - 4x) = -30<br> (Provide Step-By-Step)
Olegator [25]

Answer:

x = -5

Step-by-step explanation:

Multiply 3 by (6x - 4x) = 18x - 12x

18x - 12x = -30

6x = -30

x = -30 /6

x = -5

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3 years ago
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If f(x) and its inverse function, f–1(x), are both plotted on the same coordinate plane, what is their point of intersection?
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The Answer is D. (3,3) :)
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It takes 28 minutes for 7 people to paint 7 walls.
Ber [7]

Answer:

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8 0
3 years ago
Points Pand Q lie in plane A. How many lines contain P
jeka94

Answer:

The correct answer is :

1. Line PQ (One line PQ).

Step-by-step explanation:

The first step to solve this question is to draw the plane A with the points P and Q lying on it.

We know that given two different points there is only one line that contains this two different points.

Let's analyze each option.

''2. Lines PQ and QP''

This option is wrong because there aren't two different lines. In fact it is only one line that can be named line PQ or line QP.

''3. The 2 lines PQ and QP plus another line that does not lie in plane A.''

This option is assuming that exist three lines that contain P and Q. This option is also wrong.

''1. Line PQ''

This option is correct. It will be clarify with the drawing I will attach.

''We can't name them all!''

This option is assuming that exist infinite lines that contain P and Q. This option is wrong.

In the drawing I call the line that contains P and Q as line L.

Given that P and Q lie in plane A necessarily the line L must lie on the plane A.

8 0
3 years ago
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