Question

Find a unit vector u in the direction of v. Verify that u = 1.

Answer 1

In orde tod find the unitary vector, we need to calculate the magnitude of v. The magnitude of v is given by:

$||v||=\sqrt{0^2+(-8)^2}=8$

So, we need to divide each component of vector v by |v|:

$\begin{gathered} u=\langle\frac{0}{8},-\frac{8}{8}\rangle=\langle0,-1\rangle \\ as_{\text{ }}we_{\text{ }}can_{\text{ }}see: \\ ||u||=\sqrt{0+(-1)^2}=1 \end{gathered}$

Answer:

u = <0,-1>