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Tom [10]
3 years ago
14

The area of a rectangle is represented by the polynomial x^2+3x-6x-18. What are the length, width, and area of the rectangle if

x=12?
Mathematics
1 answer:
Nitella [24]3 years ago
5 0

Answer:

Length = 15

Width = 6

Area = 90

Step-by-step explanation:

Area of the rectangle = {x}^{2}  + 3x - 6x - 18

Lets factorise the polynomial

=  >  x(x + 3) - 6(x + 3)

=  > (x  + 3)(x - 6)

We know that Area = Length × Width

Let the length be (x + 3) & width be (x - 6)

Its given in the question that x = 12. So putting the value of x gives ,

Length = x + 3 = 12 + 3 = 15

Width = x - 6 = 12 - 6 = 6

Area = Length × Width = 15 × 6 = 90

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Answer:

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\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\=========================

\text{We have}\ y=\dfrac{1}{5}x+10\to m_1=\dfrac{1}{5}\\\\\text{Therefore}\ m_2=-\dfrac{1}{\frac{1}{5}}=-5.\\\\\text{Put the value of a slope and the coordinates of the point (-3, 5)}\\\text{to the equation}\ y=mx+b:\\\\5=-5(-3)+b\\5=15+b\qquad\text{subtract 15 from both sides}\\-10=b\to b=-10\\\\\text{Finally:}\\\\y=-5x-10

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3 years ago
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1 year ago
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