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Tom [10]
3 years ago
14

The area of a rectangle is represented by the polynomial x^2+3x-6x-18. What are the length, width, and area of the rectangle if

x=12?
Mathematics
1 answer:
Nitella [24]3 years ago
5 0

Answer:

Length = 15

Width = 6

Area = 90

Step-by-step explanation:

Area of the rectangle = {x}^{2}  + 3x - 6x - 18

Lets factorise the polynomial

=  >  x(x + 3) - 6(x + 3)

=  > (x  + 3)(x - 6)

We know that Area = Length × Width

Let the length be (x + 3) & width be (x - 6)

Its given in the question that x = 12. So putting the value of x gives ,

Length = x + 3 = 12 + 3 = 15

Width = x - 6 = 12 - 6 = 6

Area = Length × Width = 15 × 6 = 90

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Please Answer <br><br> This is due by tomorrow night and I need help
labwork [276]

Answer:

AY = 16

IY = 9

FG = 30

PA = 24

Step-by-step explanation:

<em>The </em><em>centroid </em><em>of the triangle </em><em>divides each median</em><em> at the ratio </em><em>1: 2</em><em> from </em><em>the base</em>

Let us solve the problem

In Δ AFT

∵ Y is the centroid

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→ By using the rule above

∴ Y divides AP at ratio 1: 2 from the base FT

∴ AY = 2 YP

∵ YP = 8

∴ AY = 2(8)

∴ AY = 16

∵ PA = AY + YP

∴ AP = 16 + 8

∴ AP = 24

∵ Y divides TI at ratio 1: 2 from the base FA

∴ TY = 2 IY

∵ TY = 18

∴ 18 = 2

→ Divide both sides by 2

∴ 9 = IY

∴ IY = 9

∵ Y divides FG at ratio 1:2 from the base AT

∴ FY = 2 YG

∵ FY = 20

∴ 20 = 2 YG

→ Divide both sides by 2

∴ 10 = YG

∴ YG = 10

∵ FG = YG + FY

∴ FG = 10 + 20

∴ FG = 30

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