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barxatty [35]
1 year ago
5

Help pls not graded test

Mathematics
1 answer:
Arte-miy333 [17]1 year ago
3 0

The missing angle of the given triangle  is 59°.

What is vertically opposite angles?

  Angles that are vertically opposed to one another are always equal to one another. A vertical angle and the angle to which it is next are also supplementary angles; that is, they sum up to 180 degrees. As an illustration, if two lines connect to form an angle, say X=45°, then the angle's opposite angle is also 45°.

Here consider angle with 31° and 49° triangle is 1. We know that sum of all angles in triangle is add upto 180°. Then,

⇒ 49°+31°+x = 180°

⇒ 80° + x= 180°

⇒x= 180°-80°=100°

Then unknown angle in triangle 1 ia 100°.

Now according to the vertically opposite angle theorem , opposite angles are equal to each other. Then ,

In triangle 2 angle is 100° and 21°. Then missing angle is,

⇒ 100°+21°+missing angle =180°

⇒Missing angle = 180°-100°-21°

⇒Missing angle = 59°

Therefore the answer is 59°.

To learn more about Vertical angle ,

brainly.com/question/18450499

#SPJ13

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77julia77 [94]
I'm not sure what you are looking for but I'll answer this question based on what I think is needed.

Given:
Day 1: 130 
Day 2: 130 x 4 = 520
Day 3: 520 x 4 = 2,080

The exponential equation of this problem is:
V(n) = 130(4)^n

Where n is the number of days since the video was first shown.

Let us assume that 10 days have past. Total view would be:

V(n) = 130(4)^n

V(10) = 130(4)^10
V(10) = 130(1,048,576)
V(10) = 136,314,880

After 10 days, there are more than 136 Million views of the viral video.



5 0
2 years ago
Would the answer be b an d for this
Paladinen [302]
Answer by answer key by key question equals equation
3 0
3 years ago
Read 2 more answers
Give me an example of an irrational number that is greater than 10
Pavel [41]

To find:

An irrational number that is greater than 10.

Solution:

Irritation number: It cannot be expression in the form of \dfrac{p}{q}, where, q\neq 0, p,q are integers.

For example: \sqrt{2}\sqrt{3},\pi, 1.263689...,etc..

We know that square of 10 is 100. So, square root of any prime number is  an example of an irrational number that is greater than 10.

First prime number after 100 is 101.

Required irrational number =\sqrt{101}

Therefore, \sqrt{101} is an irrational number that is greater than 10.

5 0
3 years ago
Point A is located at (-2, -6) and is translated 4 units up. What are the coordinates of point A'?
defon

Answer:

(-2, -2)

Step-by-step explanation:

Red point represents (-2,-6) while blue point represents (-2,-2). count the numbers upward and it'll be 4 units. Best thing to do in this problem is to plot the given points and go from there.

4 0
2 years ago
Read 2 more answers
Calculate the mean, median, mode, range, and 5 Number Summary of the following data set: 5,6,8,4,7,5,4,2,5,6,5,2,1,4
Artist 52 [7]

Answer:

mean = 4.57, median = 5 , mode = 5, range =7 ,

five number summary: Minimum value= 1 , First Quartile = 4, Median = 5

Third Quartile  = 6, Maximum value = 8

Step-by-step explanation:

First arrange the data in ascending order.

1,2,2,4,4,4,5,5,5,5,6,6,7,8

Mean = sum of all numbers / total numbers

         = 1+2+2+4+4+4+5+5+5+5+6+6+7+8 / 14

         = 64 / 14

         = 4.57

Median:

Since the given data is even number so, we can find median by taking mean of 2 middle numbers.

so the middle numbers are 7th and 8th  data i.e, 5 and 5

Median =(5+5)/2

           = 5

Mode:

The most repetitive number in the data set is mode

So Mode = 5

Range:

Range can be found by subtracting smallest number from largest number in the data set.

Smallest number  = 1, Largest number = 8

Range= Largest number - Smallest number

        = 8-1 = 7

Five no Summary

Minimum value= 1

First Quartile ( 25 % mark )= 4

Median = 5

Third Quartile (75 % mark) = 6

Maximum value = 8

First quartile can be found by : consider the data on left of the median and find median among them

Third quartile can be found by:  consider the data on right of the median and find median among them

7 0
3 years ago
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