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Shkiper50 [21]
3 years ago
8

Can someone please let answer day 17???

Mathematics
1 answer:
erik [133]3 years ago
6 0

Answer:

16

Step-by-step explanation:

16 - 10 =4

4/2=2

2*2=

<h2>8</h2>
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Use formula A=LW to find the length of a rectangle when the width is 35 ft and the area is 1,750 sq ft
Ludmilka [50]

Answer:

the length of the rectangle is 50 ft

Step-by-step explanation:

A-LW

1,750=L(35)

divide both sides by 35

L= 50

6 0
2 years ago
Find f(-11/5) if f(n) = 5n + 6
V125BC [204]

Answer:

f(-11/5) = -5

Step-by-step explanation:

f(n) = 5n + 6

Let x = -11/5

f(-11/5) = 5*-11/5 +6

          = -11 +6

           = -5

5 0
3 years ago
A system of equations is shown below.
prisoha [69]

Given:

The system of equations is

y=1.5x-3

y=1.5x+4

To find:

The true statement about the given system of equations.

Solution:

The slope intercept form of a line is

y=mx+b

Where, m is the slope and b is the y-intercept.

We have,

y=1.5x-3

y=1.5x+4

On comparing these two lines with slope intercept form, we get

m_1=1.5,b_1=-3

m_2=1.5,b_2=4

Since the slopes of the lines are equal but the y-intercepts are different, therefore, the two lines are parallel and the system has no solution.

Therefore, the correct option is A.

5 0
3 years ago
The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m
photoshop1234 [79]

Answer: 0.1353

Step-by-step explanation:

Given : The mean of failures =  0.025 per hour.

Then  for 8 hours , the mean of failures = \lambda=8\times0.25=2 per eight hours.

Let X be the number of failures.

The formula to calculate the Poisson distribution is given by :_

P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}

Now, the probability that the instrument does not fail in an 8-hour shift :-

P(X=0)=\dfrac{e^{-2}2^0}{0!}=0.1353352\approx0.1353

Hence, the the probability that the instrument does not fail in an 8-hour shift = 0.1353

7 0
3 years ago
​Recently, a random sample of 13-18 year olds was​ asked, "How much do you currently have in​ savings?" The data in the table re
Sonbull [250]

Answer:

μ = 235.38

σ = 234.54

Step-by-step explanation:

Assuming the table is as follows:

\left[\begin{array}{cc}Savings&Frequency\\\$0-\$199&339\\\$200-\$399&86\\\$400-\$599&55\\\$600-\$799&18\\\$800-\$999&11\\\$1000-\$1199&8\\\$1200-\$1399&3\end{array}\right]

This is an example of grouped data, where a range of values is given rather than a single data point.  First, find the total frequency.

n = 339 + 86 + 55 + 18 + 11 + 8 + 3

n = 520

The mean is the expected value using the midpoints of each range.

μ = (339×100 + 86×300 + 55×500 + 18×700 + 11×900 + 8×1100 + 3×1300) / 520

μ = 122400 / 520

μ = 235.38

The variance is:

σ² = [(339×100² + 86×300² + 55×500² + 18×700² + 11×900² + 8×1100² + 3×1300²) − (520×235.38²)] / (520 − 1)

σ² = 55009.7

The standard deviation is:

σ = 234.54

6 0
3 years ago
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