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3 years ago

Lowest term fractio 15/20

Mathematics

2 answers:

Veronika [31]3 years ago

4 0

Answer:

that could be 1/3

Step-by-step explanation:

i simplified the answer

svp [43]3 years ago

3 0

Answer: 15/20 simplified to lowest terms is 3/4.

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PLZ ANSWER ASAP 100 POINTS AND BRAINLIEST PLZ PLZ HELP

abruzzese [7]

Answer:

Yes one pair of the opposite sides could measure 10 inches , and the other pair could measure 13 inches.

Step-by-step explanation:

A parallelogram have opposite sides parallel and congruent

the given quadrilateral is a parallelogram then

10 = x + 2 Equation A

x + 5 = 2x - 3 Equation B

Solving for Equation A:

x = 10 -2 = 8 inches

Solving for Equation B;

2x - x = 5 + 3

x = 8 inches

Value X are the same equations.

Means that

For x=8 inches opposite side

So Yes one pair of the opposite sides could measure 10 inches , and the other pair could measure 13 inches.

4 0

3 years ago

The heights of some sunflowers are shown below.

deff fn [24]

Answer:

2 sunflowers

Step-by-step explanation:

Number of sunflowers that are 7 feet tall = 4

Number of sunflowers that are 5 1/2 feet tall = 2

4 - 2 = 2

8 0

3 years ago

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How do you write 0.27777777777777..... as a whole number

Agata [3.3K]

Answer:

i think 27777777777777/100000000000000

Step-by-step explanation:

8 0

3 years ago

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It took a car 3 days to travel 3106 miles. What was this car's average speed, in miles per hour? (round to the nearest mile per

Daniel [21]

Answer:

43 mph

Step-by-step explanation:

1 day = 24 hours

3 days = 3 × 24 hours = 72 hours

The car taveled 3106 miles in 72 hours.

average speed = distance/time

average speed = (3106 miles)/(72 hours)

average speed = 43 mph

8 0

3 years ago

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Which of the following points would be a solution to this system of linear inequalities?

pychu [463]

Let's plug in both x and y values in the equation and check if the inequality is true...

$\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}$

$(4,1) \\ y \leqslant x + 1 \\ y < - \frac{x}{2} - 1$

Substitute x as 4 and y as 1

$1 \leqslant 4 + 1 \\ 1 < - \frac{4}{2} - 1$

$0 \leqslant 4 + 1 \\ 1 < - 2 - 1$

$0 \leqslant 5 \\ 1 < - 3$

This is not a solution because both are not true, Only one equation is giving true as answer which is not correct!~

$\purple{ \rule{300pt}{3pt}}$

$(0, - 3) \\ y \leqslant x + 1 \\ y < - \frac{x}{2} - 1$

Substitute x as 0 and y as -3

$- 3 \leqslant 0 + 1 \\ - 3 < - \frac{0}{2} - 1$

$- 3 \leqslant 1 \\ - 3 < - 0 - 1$

$- 3 \leqslant 1 \\ - 3 < - 1$

This is a solution because both are true, Both the equations are true which means the ordered pair is a solution!~

Thus, Option B (0,-3) is the correct choice....

6 0

3 years ago

Lowest term fractio 15/20​

Lowest term fractio 15/20