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bonufazy [111]
1 year ago
5

-1 < 9 + n < 17Solve and graph solution?

Mathematics
1 answer:
Elina [12.6K]1 year ago
5 0

We have the inequality:

-1

Now, in order to solve, we will do as follows:

n will take all the values from -9 to 7, any number smaller than -9 will make it false and any number greater than 7 will make it false.

Now, in order to graph the solution, we will have:

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surface area of a cube is the sum of areas of all the faces of cube , that covers it . the formula for the surface area is equal to six times of square of length of the sides of cubes , it is represented by 6a^2 , where a is the side length of cube , it is basically the total surface area.

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What is the equation of the rational function g(x) and its corresponding slant asymptote?
bija089 [108]

The solution to the Questions are

  • The alternate hypothesis demonstrates that there are two possible outcomes for the test.
  • Decision rule: If z > 2.05 or z<-2.05, reject H0
  • z=2.59
  • The two-tailed nature of the test is shown by the alternative hypothesis.
  • The result of the test yields the following P-value: 0.0096

<h3>What is the alternate hypothesis?</h3>

(a)

The alternate hypothesis demonstrates that there are two possible outcomes for the test.

(b)

Here we have

n_{1}=40,\\\\ \bar{x}_{1}=102,\sigma_{1}=5,n_{2}=50,\bar{x}_{2}=99,\sigma_{2}=6

(b)

Here the test is two-tailed. So for \alpha =0.04, the critical values of the z-test are -2.05 and 2.05.

Decision rule: If z > 2.05 or z<-2.05, reject H0

(c)

Test statistics will be

z=\frac{(\bar{x}_{1}-\bar{x}_{2})-(\mu_{1}-\mu_{2})}{\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}}  \\\\\\z=\frac{(102-99)-(0)}{\sqrt{\frac{5^{2}}{40}+\frac{6^{2}}{50}}}

z=2.59

(d)

The two-tailed nature of the test is shown by the alternative hypothesis.

(e)

The result of the test yields the following P-value: 0.0096

Read more about P-value

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yes

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in a multiplication problem, if the first factor has 5 digits after the decimal and the second factor has 4 digits after the dec
STatiana [176]
9 digits after the decimal because 5+4=9
4 0
4 years ago
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A barrel contains 1513 liters of water. 34 of the water was used to water plants.
Korolek [52]
Considering that 34% of the total quantity of water was used to water the plants we can get to the solution of the problem.
Total quantity of water in the barrel = 1513 liters
Percent of water used for watering the plants = 34%
Then
Quantity of water used to water the plants = (34/100) * 1513
                                                                     = 514.42 liters
So 514.42 liters of water was used from the barrel to water the plants.
Quantity of water left in the barrel = 1513 - 514.42 liters
                                                      = 998.58 liters
So the quantity of water that is left in the barrel after watering the plants is 998.58 liters.
If you have said in the question that 3/4 of the total quantity of water was used for watering the plants, then the solutions would be as given below
Quantity of water used for watering the plants = (3/4) * 1513 liters
                                                                          = 1134.75 liters
Amount of water left in the barrel after watering the plants = 1513 - 1134.75 liters
                                                                                             = 378.25 liters.
8 0
4 years ago
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