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lisov135 [29]
4 years ago
15

7x^2-16x-28=0, what’s the answer

Mathematics
1 answer:
slava [35]4 years ago
3 0
Answer:
The solutions of the equation are \frac{8+2 \sqrt{65} }{7} and \frac{8-2 \sqrt{65} }{7}

Explanation:
The general form of the quadratic equation is:
ax² + bx + c = 0
The given equation is:
7x² - 16x - 28 = 0

By comparing:
a = 7
b = -16
c = -28

Now, to get the roots, we will use the quadratic formula shown in the attached image.

Substitute with the values of a, b and c and calculate the corresponding roots.

You will get the roots:
\frac{8+2 \sqrt{65} }{7} and \frac{8-2 \sqrt{65} }{7}

Hope this helps :)

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WHATS THE FRACTION FOR 6 DOLLARS AND 14 CENTS
Jet001 [13]

Answer:

6\frac{14}{100}

Step-by-step explanation:

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\frac{14}{100}

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3 0
3 years ago
LT1 10th grade level
Anton [14]

Answer:

The distance between the pirate and the treasure can be found from the following relationship between ΔEAF and ΔABC;

\overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC} = \overline{EF}/\overline{BC}

Step-by-step explanation:

From the question diagram, we have two triangles, ΔEAF and ΔABC;

The ratio of the lengths of the sides \overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC}

∠EAF and ∠BAC are vertical angles, therefore ∠EAF = ∠BAC

Therefore, ΔEAF and ΔABC are similar triangles by Side-Angle-Side, SAS, rule of similarity which states that two triangles that have ratios of a pair of their corresponding sides and the two sides also form equal angles within each triangle, then the two triangles are similar

Therefore, the ratio of the each pair of corresponding sides of the two triangles are equal

We have;

\overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC} = 50 ft. /(100 ft.) =  \overline{EF}/\overline{BC} = \overline{EF}/120 ft.

\overline{EF} = 120 ft. × 50 ft./(100 ft.) = 60 ft.

\overline{EF} = 60 ft.

The distance between the pirate and the treasure, \overline{EF} = 60 ft.

4 0
3 years ago
Almost doneeeeeee help meeeeeeee it was due yesterday
Ann [662]

Answer:

Okay. I got:

FGCE

Step-by-step explanation:

6 0
3 years ago
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