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Tanya [424]
4 years ago
9

Round each number to the nearest tenth.

Mathematics
2 answers:
cupoosta [38]4 years ago
3 0
B,
the exact answer is 84.96, so most likely rounded,

RULES:
5 or above, shove it up.
4 or below, leave it.

9 is higher than 5, obviously.

So, B is the answer.

~MisterMistyEyed
kobusy [5.1K]4 years ago
3 0
382.24-297.28= 84.96
Answer: B 85
To round a number it must be 5 or higher so since the nine in .9 is higher than five it raises the number to 85. And there are no numbers after that. That is the rule so it goes for any other ones too like, 100th or 1000th.
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What is the mean of 5, 8, 16, 22, 19, 27, 32? (Round to the nearest whole number.)
Artyom0805 [142]

Answer:

B) 18.

Step-by-step explanation:

Add them up then divide by the amount of numbers there are.

7 0
4 years ago
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Write 4408730 in expanded form
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4000000+400000+8000+700+30

5 0
3 years ago
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The height of a trapezoid is 8 in. And its area is 96 in2. One base of the trapezoid is 6 inches longer than the other base. Wha
Vsevolod [243]

Answer:

The lengths of the bases are 9 inches and 15 inches.

Step-by-step explanation:

The area of trapezoid is

=\frac12(\textrm{ sum of parallel sides})\times height

Given that the height of a trapezoid is 8 in. and its area is 96 in².

Assume the bases of the trapezoid be b₁ and b₂.

Since one base of the trapezoid 6 in. longer than the other.

Let, b₁=b₂+6

The area of the trapezoid is

=\frac 12 (b_1+b_2)\times8 in²

=\frac12 (b_2+6+b_2)\times 8 in²

=\frac12(2b_2+6)\times8 in²

According to the problem,

\frac12(2b_2+6)\times8 =96

\Rightarrow 2b_2+6=\frac{96\times 2}{8}                [ Multiplying \frac28 ]

\Rightarrow 2b_2+6=24

\Rightarrow 2b_2=24-6

\Rightarrow 2b_2=18

\Rightarrow b_2=\frac{18}{2}

\Rightarrow b_2=9

Then, b_1=b_2+6

              =9+6

             =15 in

The lengths of the bases are 9 inches and 15 inches.

5 0
4 years ago
Solve each equation <br> For points!!
Whitepunk [10]

Answer:

X = 13

X = 13

X = 13

X = 98

X = 8

<u><em>Please mark as brainliest </em></u>

Have a great day, be safe and healthy  

Thank u  

XD

8 0
3 years ago
A tank contains 250 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
VashaNatasha [74]

Answer:

A(t)=250-210e^{-\frac{t}{50}}

Step-by-step explanation:

We are given that

Volume,V=250 L

Mass of salt=m=40 g

Brine containing 1 g per liter

Pumped into the tank at the rate=5 L/min

We have to find the number A(t) of grams of salt in the tank at time t.

Rate of change of salt in the tank

\frac{dA}{dt}=Rate in-Rate out

Rate in=5 L/min

Rate out=\frac{A}{250}\times 5=\frac{A}{50} L/min

\frac{dA}{dt}=5-\frac{A}{50}=\frac{250-A}{50}

\int \frac{50dA}{250-A}=\int dt

-50ln(250-A)=t+C

Using the formula

\int \frac{dx}{x}=ln x

A=40 and t=0

-50ln(250-40)=0+C

-50ln(210)=C

Substitute the value

-50ln(250-A)=t-50ln(210)

-50ln(250-A)+50ln(210)=t

50ln\frac{210}{250-A}=t

t=50ln\frac{210}{250-A}

\frac{t}{50}=ln\frac{210}{250-A}

\frac{210}{250-A}=e^{\frac{t}{50}

\frac{250-A}{210}=e^{-\frac{t}{50}}

250-A=210e^{-\frac{t}{50}}

A(t)=250-210e^{-\frac{t}{50}}

8 0
4 years ago
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