I believe 50% of 284 =<em>142</em>
Answer:
5/3
Step-by-step explanation:
z = (Distributed score - Mean)/Standard deviation= (80-70)/6 = 5/3
The temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Given that,
- The ground temperature at the airport is 10 °C.
- The decrease in temperature is 5.4°C for each & every rise in 1 kilometer.
Based on the above information, the temperature outside should be
The decrease in the temperature should be
= 5.4×5
= 27°C
Now the final temperature is
= 10 - 27
= -17°C
Therefore we can conclude that the temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Learn more: brainly.com/question/20459283
Before translation, coordinate C was: (3, 1)
Now, Translation factor is: <span>(x, y) → (x+4, y−6).
So, Coordinates of C' = (3 + 4, 1 - 6) = (7, -5)
In short, Your Answer would be Option D
Hope this helps!</span>