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Schach [20]
2 years ago
8

The ground temperature at an airport is 10 °C. The temperature decreases by 5.4 °C for every increase of 1 kilometer above the g

round. What is the temperature outside a plane flying at an altitude of 5 kilometers?
Mathematics
1 answer:
Paraphin [41]2 years ago
5 0

The temperature outside a plane flying at an altitude of 5 kilometers is -17°C.

Given that,

  • The ground temperature at the airport is 10 °C.
  • The decrease in temperature is 5.4°C for each & every rise in 1 kilometer.

Based on the above information, the temperature outside should be

The decrease in the temperature should be

= 5.4×5

= 27°C

Now the final temperature is

= 10 - 27

= -17°C

Therefore we can conclude that the temperature outside a plane flying at an altitude of 5 kilometers is -17°C.

Learn more: brainly.com/question/20459283

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Find the base of an isosceles triangle whose area is 60 cm² and the length of one of its equal sides is 13 cm. ​
Kobotan [32]

Answer:

Base = 24 cm or 10cm

Step-by-step explanation:

REMEMBER:
An isosceles triangle ABC with base BC = ‘b' & height AD = ‘h' & its equal sides =13 cm & area = 60 cm²

Using the formulas

A=\frac{bh_b}{2}

h_b=\sqrt{a^2-\frac{b^2}{4} }

There are 2 solutions for b

b=2\sqrt{2}   \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2+\sqrt{13^4-4*60^2} } } ≈ 10cmb=2\sqrt{2}   \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2-\sqrt{13^4-4*60^2} } }=24cm

Less complex:

Area of a triangle = 1/2 * b * h = 60

=> h = 120/b

In right triangle ABD

13² = h² + b² /4 ( by Pythagoras law)

=>169 = 120²/b² + b²/4

=>676 b² = 57600 + b^4

=> b^4 - 676 b² + 57600 = 0

=> b² = 676 +- √(676² - 4*57600) / 2

=> b²= 676 +- √(226576) /2

=> b² = (676 +- 476 )/2

=> b² = 1152/2 , 200 /2

=> b² = 576 , 100

=> b = 24, 10

So, Base = 24 cm or 10cm

4 0
2 years ago
Help I need the intercept please.
Gnesinka [82]
The x-intercept would be (6,0)
8 0
2 years ago
If the radius of mars is about 13.7% of neptune's radius, what is the radius of neptune?
Marianna [84]
The volumetric mean radius of Mars is about 3389.5 km. We know that it's 13.7% of Neptune's mean radius, so we can write it down as:

3389.5 = 13.7% of x (where x is Neptune's radius)
3389.5 = 13.7% x
3389.5 = 137/1000x                / * 1000 (both sides)
3389500 = 137x                       / ÷ 137 (both sides)
x = 24740.87591240876
x ≈ 24740.88

Answer: The mean radius of Neptune is about 24740.88 km.
6 0
3 years ago
A hat's original price was $50. It is on sale for 40%0ff. How much does it cost?
yKpoI14uk [10]

Answer:

30

Step-by-step explanation:

40/100 x 50= 20

50-20=30

3 0
2 years ago
Read 2 more answers
Solve equation show work
Naddika [18.5K]

Answer:

h= -8/3

Picture Explanation:

  1. Divide 3 on both sides of the equal sign, as shown above, so (h) can be alone.
  2. Since negative 8, let alone positive 8, can't be divided into 3, you simply leave the fraction as is. So you're left with (h= -8/3)

<em><u>Hope this makes sense.</u></em>

7 0
2 years ago
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