The temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
Given that,
Based on the above information, the temperature outside should be
The decrease in the temperature should be
= 5.4×5
= 27°C
Now the final temperature is
= 10 - 27
= -17°C
Therefore we can conclude that the temperature outside a plane flying at an altitude of 5 kilometers is -17°C.
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Answer:
Volume = 4πr^3/3
= 4 x 3.14 x 4.7/2 x 4.7/2 x 4.7/2 x 1/3
= 39.5 (approx.)
Hope this helps!
Answer: D) Reflection across the y-axis; counterclockwise rotation about the origin
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