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3 years ago

System AAA \text{\quad}start text, end text System BBB

Mathematics

2 answers:

babymother [125]3 years ago

5 0

Answer:

B for 1 and A for 2

Step-by-step explanation:

lisabon 2012 [21]3 years ago

4 0

Answer:

replace one question with itself where the same quantity is added to both sides and yes

Step-by-step explanation:

The other answer is wrong :)

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Complete the statements about circle Z.

exis [7]

Answer:

PLEASE GIVE BRAINLYST

1) UZV

2)the center of a circle

3)WSX

4) equal to

5)79 degrees

THESE ARE ALL CORRECT

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Which polynomial is equivalent to (11r – 8) + (5r - 9)?

pickupchik [31]

<h3>Answer: 16r - 17</h3>

Work Shown:

(11r - 8) + (5r - 9)

11r - 8 + 5r - 9

(11r+5r) + (-8-9)

16r - 17

4 0

3 years ago

PLEASE HELP IM ON A TIMED TEST

Mila [183]

Answer:

third term

Step-by-step explanation:

hope this helped

6 0

3 years ago

EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =

geniusboy [140]

The Lagrangian,

$L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)$

has critical points where its partial derivatives vanish:

$L_x=1-\lambda-2\mu x=0$

$L_y=2+\lambda-2\mu y=0$

$L_z=9-\lambda=0$

$L_\lambda=x-y+z-1=0$

$L_\mu=x^2+y^2-1=0$

$L_z=0$ tells us $\lambda=9$ , so that

$L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu$

$L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}$

Then with $L_\mu=0$ , we get

$x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2$

and $L_\lambda=0$ tells us

$x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}$

Then there are two critical points, $\left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right)$ . The critical point with the negative $x$ -coordinates gives the maximum value, $9+\sqrt{185}$ .

8 0

4 years ago

Find the first fourth and eighth terms of A(n)=-2•5^n-1

Mila [183]

The first term is 0. The fourth is 1000. The eighth term is 10,000,000. All you have to do is plug the term you want to find into n and then solve.

5 0

3 years ago