Answer:
the answer is x=2 and y=3
Step-by-step explanation:
y=3 for x=2
y=3;x=2
x=2 and y=3
Answer:
66 HR
Step-by-step explanation:
We can set up an equivalent proportion and cross-multiply like this:
22/7=x/21
Cross multiply.
7x=462
Divide by 7 on both sides.
x=66
HTH :)
Answer:
![\dfrac{\$1000+\$20x}{x} \leq \$25](https://tex.z-dn.net/?f=%5Cdfrac%7B%5C%241000%2B%5C%2420x%7D%7Bx%7D%20%5Cleq%20%5C%2425)
Minimum 200 people other than the 2 charity representatives.
Step-by-step explanation:
Given that:
The venue can hold a maximum of 500 people.
Cost of venue = $1000
Per person cost for food = $20
Two charity representatives get to attend the dinner for free.
To find:
The inequality and to determine how many people must come to keep costs at most $25.
Solution:
Let the number of people attending the dinner = ![x](https://tex.z-dn.net/?f=x)
Cost of food for
people = ![\$20x](https://tex.z-dn.net/?f=%5C%2420x)
Total cost = $1000 + ![\$20x](https://tex.z-dn.net/?f=%5C%2420x)
Cost per person = Total cost divided by Number of people attending the dinner.
As per question statement:
![\dfrac{\$1000+\$20x}{x} \leq \$25\\\Rightarrow 1000+20x\leq25x\\\Rightarrow 1000 \leq 5x\\\Rightarrow x\geq 200](https://tex.z-dn.net/?f=%5Cdfrac%7B%5C%241000%2B%5C%2420x%7D%7Bx%7D%20%5Cleq%20%5C%2425%5C%5C%5CRightarrow%201000%2B20x%5Cleq25x%5C%5C%5CRightarrow%201000%20%5Cleq%205x%5C%5C%5CRightarrow%20x%5Cgeq%20200)
Therefore, the answer is:
Minimum 200 people other than the 2 charity representatives should attend the dinner.
The awnser is 38si hope this helps