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Rudiy27
3 years ago
14

Find the geometric mean between 4 square root of 3 and 10 square root of 3

Mathematics
1 answer:
maria [59]3 years ago
3 0
Hello,
4√3*10√3=40*3=120
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Write the equation of the line that passes through the points (2, 3) and (3, -7). Put
FrozenT [24]

Answer:

y - 3 = -10 (x-2)

Step-by-step explanation:

The point-slope formula is y-y_1 = m (x-x_1). When knowing the slope of a line and a point it intersects, we can write its equation with that formula. Substitute m, x_1, and y_1 for real values.

1) First, find m, or the slope. Use the slope formula m = \frac{y_2-y_1}{x_2-x_1} and substitute the x and y values of the given points. Then, solve:

m = \frac{(-7)-(3)}{(3)-(2)} \\m = \frac{-7-3}{3-2} \\m = \frac{-10}{1} \\m = -10

Therefore, the slope of the line is -10.

2) Now, substitute the needed real values into the point-slope formula, y-y_1 = m (x-x_1). Since m represents the slope, substitute -10 in its place. Since x_1 and y_1 represent the x and y values of a point the line crosses, choose any of the points given and substitute its values into the formula. (Either one is fine, they both equal the same thing. I chose (2,3).) This will give the following answer and equation:

y - 3 = -10 (x-2)

7 0
3 years ago
JWISOSOOS someone help me n show me how to do it 2. Thanks goodnight:>>
posledela

Answer:

2/3(3x+9)=-2(2x+6)

2/3(3x+2x)=-2(9+6)

2/3×5x=-2+15

10x/3=13

3x=13

x=13-3

x=10

4 0
3 years ago
In the isosceles triangle ABC, we have AB=AC=4. The altitude from B meets AC at H. If AH=3(HC) then determine BC.
Inga [223]

Answer:

BC=√7

Step-by-step explanation:

AC=4

AC=AH+HC

=3HC+HC

=4HC

HC=1/4AC=1/4×4=1

AH=3HC=3×1=3

BH⊥ AC

AB=AC=4

BC=\sqrt{AB^2-AH^2} =\sqrt{4^2-3^2} =\sqrt{16-9} =\sqrt{7}

5 0
3 years ago
Write and solve an equation for the total number of possible combinations from flipping a coin 10 times. Please help quick, I'm
Furkat [3]
The total number of possible combinations from flipping a coin 10 times is 2^10 = 1024.
3 0
3 years ago
Read 2 more answers
A dilation with a scale factor of 3. 5 and centered at the origin is applied to PQ¯¯¯¯¯ with endpoints P(2, 5) and Q(2, 1)
velikii [3]

Answer: The answer is P'(7, 17.5) and Q'(7, 3.5).

Step-by-step explanation:  Given that a line segment PQ is dilated with a scale factor of 3.5 where origin is the centre of dilation.

The end points of segment PQ are P(2, 5) and Q(2, 1).

Therefore, after dilation, the coordinates of the end points become

Thus, the coordinates of P' are (7, 17.5) and the co-ordinates of Q' are (7, 3.5).

7 0
2 years ago
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