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Rudiy27
3 years ago
14

Find the geometric mean between 4 square root of 3 and 10 square root of 3

Mathematics
1 answer:
maria [59]3 years ago
3 0
Hello,
4√3*10√3=40*3=120
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Una persona pensó hacer una obra en 15 días; pero tardó 10
Ivenika [448]

Answer:

<em>Trabajó 3 horas al día</em>

Step-by-step explanation:

<u>Proporcionalidad</u>

Una persona planeó terminar la obra en 15 dias, pero tardó 10 dias adicionales porque trabajó 2 horas menos por día.

Usaremos proporciones para calcular las horas de trabajo diarias.

Si 2 horas diarias representan 10 dias de atraso, entonces cada hora representa 5 dias de trabajo.

Si la obra tardaba 15 dias, entonces la persona trabajó 15/5 = 3 horas diarias.

8 0
3 years ago
In an auditorium, 1/6 of the students are 5th Graders, 1/3 are 4th Graders, and 1/4 of the remaining students are 2nd graders. I
avanturin [10]
1/2 of the class are 5th and 4th
1/2 of 96= 48
1/4 of 48 =12
5 0
3 years ago
A consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 5​% will need repairs​
gtnhenbr [62]

Answer:

a) 0.5476

b) 0.0676

c) 0.4524

Step-by-step explanation:

Given this information, we can conclude that 74% of the cars won't need any repairs over a 1-year period (100 - 20 - 5 - 1 = 74%). And 26% will need at least 1 repair over a 1-year period.

P(car doesn't need repair) = 0.74

P (car needs repair) = 0.26

If you own two cars, the probability that:

<u>a) Neither will need repair:</u>

We need that car 1 won't need repair AND car 2 won't need repair.

=P(Car 1 doesn't need repair) x P(Car 2 doesn't need repair)

= 0.74 x 0.74 = 0.5476

The probability that neither will need repair is 0.5476.

<u>b) Both will need repair:</u>

We need that car 1 needs repair AND car 2 needs repair.

P(Car 1 needs repair) x P(Car 2 needs repair)

= 0.26 x 0.26 = 0.0676

The probability that both will need repair is 0.0676

<u>c) At least one car will need repair</u>

Car 1 needs repair or Car 2 needs repair or both need repair.

To solve this one, it's easier to use the complement of P(neither needs repair)

1 - P(neither needs repair)

1 - (0.74)(0.74)  = 1 - 0.5476 = 0.4524

The probability that at least one car will need repair is 0.4524

4 0
3 years ago
Work out the product of
nignag [31]
That will be 4/4/7 hope this helps
5 0
3 years ago
Help please 11 POINTS
Y_Kistochka [10]
57.10
70.9
these are only the answers for the first two problems
4 0
3 years ago
Read 2 more answers
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