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scZoUnD [109]
3 years ago
5

On a coordinate plane, kite H I J K with diagonals is shown. Point H is at (negative 3, 1), point I is at (negative 3, 4), point

J is at (0, 4), and point K is at (2, negative 1). Which statement proves that quadrilateral HIJK is a kite? HI ⊥ IJ, and m∠H = m∠J. IH = IJ = 3 and JK = HK = StartRoot 29 EndRoot, and IH ≠ JK and IJ ≠ HK. IK intersects HJ at the midpoint of HJ at (−1.5, 2.5). The slope of HK = Negative two-fifths and the slope of JK = Negative five-halves.

Mathematics
1 answer:
bekas [8.4K]3 years ago
8 0

Answer:

(B)IH = IJ = 3 and JK = HK = \sqrt{29}$ units, and IH ≠ JK and IJ ≠ HK.

Step-by-step explanation:

In a kite the following properties applies

<u>Adjacent sides are equal</u>

IH and IJ are adjacent sides

IH=IJ=3 Units

Similarly, JK and HK are adjacent sides and:

JK = HK = \sqrt{29}$ units

<u>Since opposite sides of a kite must not be equal,</u>

IH ≠ JK and IJ ≠ HK.

Therefore, Option B is the statement that proves that HIJK is a kite.

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Answer:

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Step-by-step explanation:

FGBE is a Kite. If you draw a line segment from F to B in bisects ∠GBE and ∠GFE into two triangles. The angles of a triangle with always add up to 180°. So, in triangle FBG, ∠GFB = 45° and ∠GBF = 24°. You subtract 45 and 24 from 180 and you are left with 111°.

5 0
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nasty-shy [4]

Answer:

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Step-by-step explanation:

cube: 6^3

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<em>*REMEMBER that when dealing with volume the units are cubic (whatever), in this case, its cubic inches(in^3).</em>

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3 years ago
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Use PEMDAS.

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27-6=21

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