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ozzi
1 year ago
11

Luke claims two circles are always isometric because the shape never changes. Is he correct?

Mathematics
1 answer:
olganol [36]1 year ago
3 0

Luke asserts that since the shape is constant, two circles are always isometric. he is wrong. No, an isometry keeps the size and shape intact.

Given that,

Luke asserts that since the shape is constant, two circles are always isometric.

We have to say is he accurate.

The answer is

No, an isometry keeps the size and shape intact.

Because a shape-preserving transformation (movement) in the plane or in space is called an isometric transformation (or isometry). The isometric transformations include translation, rotation, and combinations thereof, such as the glide, which combines a translation with a reflection.

Therefore, Luke asserts that since the shape is constant, two circles are always isometric. he is wrong. No, an isometry keeps the size and shape intact.

To learn more about isometric visit: brainly.com/question/110297

#SPJ1

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Shtirlitz [24]

Hi there! :)

\large\boxed{j(h(x))(2) = 31}

Solve for j(h(x)):

h(x) = x² + 4

j(x) = 4x - 1

Substitute in h(x) into "x":

j(h(x)) = 4(x² + 4) - 1

j(h(x)) = 4x² + 16 - 1

j(h(x)) = 4x² + 15

Solve at x = 2:

4(2)² + 15 = 4(4) + 15 = 31.

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3 years ago
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Lesechka [4]

Inequality 1: y ≤ 5x + 1

Inequality 2: y > x - 2


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#2. The slope is 1, the y-intercept is -2, the shaded area is above the line and the line is dotted, which means that y is greater than the equation

6 0
3 years ago
The expression 20a + 13c is the cost (in dollars) for adults and students to enter a science center. Find the total cost for 4 a
lapo4ka [179]

Answer:

$392

Step-by-step explanation:

Given the expression :

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3 years ago
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inysia [295]

Answer:

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Step-by-step explanation:

We can solve this equation using the quadratic formula OR Completing the Square method.

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the quadratic formula says:   x =  - b/ (2a)  +  root(b^2 - 4ac) / (2a)

or  x =  - b/ (2a)  -  root(b^2 - 4ac) / (2a)

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x = 6  +  root (144 - 56) / 2

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x = 6 + root(4*22) / 2

x = 6 + 2*root(22)/2

x = 6 + root(22)  = 6 + \sqrt{22}

so   x =6 + \sqrt{22}   or  x = 6 - \sqrt{22}

In this case  x = n

n = 6 + \sqrt{22}  or  n = 6 - \sqrt{22}

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3 years ago
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Semenov [28]

Answer:

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Step-by-step explanation:

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