Answer:
a. dy/dx = -2/3
b. dy/dx = -28
Step-by-step explanation:
One way to do this is to assume that x and y are functions of something else, say "t", then differentiate with respect to that. If we write dx/dt = x' and dy/dt = y', then the required derivative is y'/x' = dy/dx.
a. x'·y^3 +x·(3y^2·y') = 0
y'/x' = -y^3/(3xy^2) = -y/(3x)
For the given point, this is ...
dy/dx = -2/3
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b. 2x·x' +x^2·y' -2x'·y^3 -2x·(3y^2·y') + 0 = 2x' + 2y'
y'(x^2 -6xy^2 -2) = x'(2 -2x +2y^3)
y'/x' = 2(1 -x +y^3)/(x^2 +6xy^2 -2)
For the given point, this is ...
dy/dx = 2(1 -0 +27)/(0 +0 -2)
dy/dx = -28
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The attached graphs show these to be plausible values for the derivatives at the given points.
First, solve for the slope. This can be found by looking at the y and x intercepts. At x = 0, y = 1.5. At x = 2, y = 0.
Slope is defined as Δy/Δx, or the change in y over the change in x. This means that in order to calculate the slope, you must find the difference between the values of y and divide it by the difference in the values of x for the two points to determine the slope between them.
(0 - 1.5)/(2-0) = (-1.5)/2 = -0.75 or -3/4
Now that you have the slope, we can write the equation in slope intercept form, y = mx + b, where m is the slope we calculated and b is the y intercept, 1.5.
y = (-3/4)x + 1.5
Answer:
Step-by-step explanation:
So we know they had got $22,553 which is 90% more than last year. With this information we know:
190% = $22,553
1% = $22,553/190
1% = $118.70
100% = $11870
So overall it would be $11870 which they had got last year
All you have to do is divide 1/2 from both sides to leave a by itself , you will get 1.2
