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Rainbow [258]
1 year ago
15

Find a function f whose graph is a parabola with the given vertex and that passes through the given point.

Mathematics
1 answer:
goblinko [34]1 year ago
3 0

A parabola is an approximately U-shaped, mirror-symmetrical plane curve in mathematics. It corresponds to a number of seemingly unrelated mathematical descriptions, all of which can be shown to define the same curves. A parabola can be described using a point and a line.

A parabola equation is what is it?

A parabola's general equation is written as y = a(x - h)2 + k or x = a(y - k)2 + h.

To determine the equation of a parabola, we can utilize the vertex form. Assuming we can read the coordinates (h,k) from the graph, the aim is to utilize the coordinates of its vertex (maximum point, or minimum point), to formulate its equation in the form y=a(xh)2+k, and then to determine the value of the coefficient a.

To learn more about Parabola refer to:

brainly.com/question/25651698

#SPJ9

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A and B are two events.
maria [59]

Answer:

0.8

Step-by-step explanation:

We can solve P(A or B) by using the following:

P(AorB)=P(A)+P(B)-P(AandB)

Since we know P(A) = 0.6, P(B) = 0.3 and P(A and B) = 0.1 we obtain:

P(AorB)=0.6+0.3-0.1=0.8


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2 years ago
Find the value of x² - x+1 when x=√3 -1, in the form a+b√3 where a and b are integers​
lidiya [134]

Answer:

6-3\sqrt{3}

If you compare this to a+b\sqrt{3}, then a=6 and b=-3.

Step-by-step explanation:

We are given x=\sqrt{3}-1 and we are asked to find the value of x^2-x+1.

So we will need to find x^2.

x=\sqrt{3}-1

Square both sides:

x^2=(\sqrt{3}-1)^2

Expand using identity: (x-a)^2=x^2-2ax+a^2.

x^2=(\sqrt{3})^2-2(\sqrt{3})(1)+1^2

x^2=3-2\sqrt{3}+1

x^2=4-2\sqrt{3}

Let's go back to the full x^2-x+1.

x^2-x+1

(4-2\sqrt{3})-(\sqrt{3}-1)+1

4-2\sqrt{3}-\sqrt{3}+1+1

6-3\sqrt{3}

If you compare this to a+b\sqrt{3}, then a=6 and b=-3.

5 0
3 years ago
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