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Novosadov [1.4K]
2 years ago
11

What is the answers to

Mathematics
1 answer:
Liula [17]2 years ago
5 0

Answer:   -4/3= -1.3 repeating

Step-by-step explanation:

6g-9+5-3g    -9+5= -4     6g-3g= 3g      3g/3 cancels out.   -4/3= -1.3 repeating

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Write an expression that is equivalent to (3x-2)-x^2+2x+5), combing like terms
ss7ja [257]

Answer:

-x^2+5x+3

Step-by-step explanation:

Remove unnecessary parenthesis.

3x-2-x^2+2x+5

Collect like terms.

5x+3-x^2

Use the commutative property to reorder the terms.

-x^2+5x+3

4 0
3 years ago
If (a,1),(-2,b).(c,-3) are points on the straight line 2x + y = 3x - y +1. Find the values of a, b and c. THANK YOU FOR THR PERS
Lisa [10]

Answer:

it’s g ! i just turned it in and it’s g :)

6 0
2 years ago
Determine whether the equation is exact. If it​ is, then solve it. e Superscript t Baseline (7 y minus 3 t )dt plus (2 plus 7 e
umka21 [38]

Answer:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

Step-by-step explanation:

You have the following differential equation:

e^t(7y-3t)dt+(2+7e^t)dy=0

This equation can be written as:

Mdt+Ndy=0

where

M=e^t(7y-3t)\\\\N=(2+7e^t)

If the differential equation is exact, it is necessary the following:

\frac{\partial M}{\partial y}=\frac{\partial N}{\partial t}

Then, you evaluate the partial derivatives:

\frac{\partial M}{\partial y}=\frac{\partial}{\partial t}e^t(7y-3t)\\\\\frac{\partial M}{\partial t}=7e^t\\\\\frac{\partial N}{\partial t}=\frac{\partial}{\partial t}(2+7e^t)\\\\\frac{\partial N}{\partial t}=7e^t\\\\\frac{\partial M}{\partial t} = \frac{\partial N}{\partial t}

The partial derivatives are equal, then, the differential equation is exact.

In order to obtain the solution of the equation you first integrate M or N:

F(t,y)=\int N \partial y = (2 +7e^t)y+g(t)        (1)

Next, you derive the last equation respect to t:

\frac{\partial F(t,y)}{\partial t}=7ye^t+g'(t)

however, the last derivative must be equal to M. From there you can calculate g(t):

\frac{\partial F(t,y)}{\partial t}=M=(7y-3t)e^t=7ye^t+g'(t)\\\\g'(t)=-3te^t\\\\g(t)=-3\int te^tdt=-3[te^t-\int e^tdt]=-3[te^t-e^t]

Hence, by replacing g(t) in the expression (1) for F(t,y) you obtain:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

where C is the constant of integration

8 0
3 years ago
Dylan and his children went into a grocery store and where they sell peaches for $1 each and mangos for $0.50 each. Dylan has $1
mafiozo [28]

Answer:

8 mangoes

Step-by-step explanation:

1) lets create 2 systems of inequalities

where m=# of mangoes

            p=# of peaches

so m+p≥15 and 1m+0.5p≤15

lets substitute "13" in  the m+p inequality to see how many mangoes dylan can buy:

m+(13)≥15

subtract "13" from both sides:

m≥2

now we substitute "13" in the other inequality:

m+0.5(13)≤15

m+6.5≤15

subtract 6.5 from both sides:

m≤8.5

m≥2 and m≤8.5

seeing our restriction, we can buy 8 mangoes (since we can't have 1/2 a mango)

hope this helps!

3 0
3 years ago
PLS HELP I ONLY HAVE 5 MIN
kondor19780726 [428]

Answer:

I know this isn't really help but Desmos is a good place to help you with stuff like this.

6 0
2 years ago
Read 2 more answers
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