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3 years ago

The radius of a circle is 9 m. Find its area in terms of \piπ.

Mathematics

1 answer:

andriy [413]3 years ago

6 0

Answer:

A= 81πm² or 254.47 m²

Step-by-step explanation:

Area = π x r²

π x 9m² (9x9)

<em>i'm not 100% sure this is correct so i'm sorry if it is wrong</em>

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? QUESTION

Doss [256]

Answer:

-20

Step-by-step explanation:

y = 4x + b

-4 = 4(7) + b

-32 = b

y = 4x -32

r = 4(3) - 32

r = -20

6 0

3 years ago

Simplify the expression:<br> 9–7k+9k–k

vodomira [7]

9+k I am pretty sure

8 0

3 years ago

Is it true that 5 2/3 - 3 3/4 = 1 + 2/3 + 3/4? Prove your answer.

soldier1979 [14.2K]

Answer:

Answered

Step-by-step explanation:

Taking LHS

$5\frac{2}{3} -3\frac{3}{4}= \frac{17}{3} -\frac{15}{4}$

$\frac{17}{3} -\frac{15}{4} = \frac{68-45}{12} = \frac{23}{12}$

now solving RHS

$1+\frac{2}{3}+\frac{3}{4}=\frac{12+8+9}{12}=\frac{29}{12}$

clearly, LHS≠ RHS

hence both quantities are different from each other.

3 0

3 years ago

Read 2 more answers

the area of a rectangle is 256.5 meters squared if the length is 18 meters what is the perimeter of the rectangle

PolarNik [594]

You would do 256.5/18 to get the other side which is 14.25, then you add 18 and 14.25 getting 32.25, now multiply that by 2 because there are 2 of each length sides, and you get 64.5 meters as the perimeter

3 0

3 years ago

If sin θ = 2 over 7 and tan θ > 0, what is the value of cos θ?

sashaice [31]

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\quad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\$

$\bf sin(\theta )=\cfrac{2}{7}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{7^2-2^2}=a\implies \pm\sqrt{45}=a\implies \pm 3\sqrt{5}=a$

but.... which is it? the + or the -? well, we know that tan(θ) > 0, is another way to say that the tangent of the angle is positive, now, for the tangent to be positive, since it's opposite/adjacent both opposite and adjacent have to be the same exact sign, now, we know the opposite is +2, so that means the adjacent has to be the same sign, thus is the positive version 3√(5)

thus $\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\qquad \qquad cos(\theta )=\cfrac{3\sqrt{5}}{7}$

3 0

4 years ago