Match the vector field f with the correct plot. f(x, y) = x, −y

Mathematics

1 answer:

Goshia [24]2 years ago

8 0

Option b is true to match the vector field f with the given plot f(x, y)=x, -y

<h3>What is meant by a function?</h3>

The earliest known attempts at the concept of functions can be traced back to the work of the Persian mathematicians Al-Biruni and Sharaf al-Din al-Tusi. Originally, functions were idealized dependencies of one variable on another. For example, planetary positions are functions of time. Historically, this concept was developed in calculus towards the end of his 17th century, and the functions studied were differentiable (i.e. they had a high degree of regularity) until his 19th century ).

Given,

f(x, y) = x, -y

gt; at x⇒∞, y⇒-∞ downwards

at x⇒∞, y⇒+∞ downwards

Therefore, option b is true to match the vector field f with the given plot

f(x, y)=x, -y

To know more about function, visit:

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The complete question is as follows:

Match the vector field f with the correct plot. f(x, y) = x, −y

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Identify the lateral area and surface area of a regular square pyramid with base edge length 11 cm and slant height 15 cm, round

Ann [662]

The surface area of the square pyramid is: 451 cm²

The lateral surface area of the square pyramid = 330 cm²

<h3>What is the Lateral Surface Area and Surface Area of a Square Pyramid?</h3>

Surface area = a² + 2al, where a is the base edge and l is the slant height.

Lateral Surface Area = 2al.

Given the following:

a = 11 cm
l = 15 cm

Surface area = a² + 2al = 11² + 2(11)(15)

Surface area = 451 cm²

Lateral Surface Area = 2al = 2(11)(15)

Lateral Surface Area = 330 cm²

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3 0

2 years ago

Read 2 more answers

I NEED HELP ON THIS PROBLEM!!! PLEASE

Allushta [10]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$5x+8y=-9\implies 8y=-5x-9\implies y=\cfrac{-5x-9}{8} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{5}{8}} x-9\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

well then, so since this equation has that slope therefore

$\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{-5}{8}} ~\hfill \stackrel{reciprocal}{\cfrac{8}{-5}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{8}{-5}\implies \cfrac{8}{5}}}$

so we're really looking for the equation of a line whose slope is 8/5 and runs through (10,10)

$(\stackrel{x_1}{10}~,~\stackrel{y_1}{10}) ~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{8}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{\cfrac{8}{5}}(x-\stackrel{x_1}{10})$