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3241004551 [841]
1 year ago
7

4 minus the cube of a number?

Mathematics
1 answer:
Sunny_sXe [5.5K]1 year ago
5 0

the final answer is

x^3-4

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Suppose that the functions and s are defined for all real numbers x as follows.
abruzzese [7]

(r*s) = (x+1)(3x+4) = 3x² + 3x + 4x + 4 = 3x² + 7x + 4

(r-s)(x) = x+1 - (3x+4) = x + 1 - 3x - 4 = -2x - 3

(r+s)(x) = x + 1 + 3x + 4 = 4x + 5

(r + s)(2) = 4(2) + 5 = 8 + 5 = 13

<h3>What is algebraic expression?</h3>

A number, a variable, or a mix of numbers, variables, and operation symbols make up an expression. Two expressions joined by an equal sign form an equation. Word illustration: The product of 8 and 3. Word illustration: The product of 8 and 3 is 11

to learn more about algebraic expression refer to:

brainly.com/question/4344214

#SPJ9

7 0
2 years ago
Factor theorem ...first part​
ira [324]

Answer:

(-∞, -2) and (2, ∞)

Step-by-step explanation:

ƒ(x) = x³ -12x + 10

f'(x) = 3x² - 12  

Set 3x² - 12 = 0

        x² -  4 = 0

              x² = 4

               x = ±2

The points x = -2 and x = + 2 divide the number line into three intervals:

(-∞, -2), (-2, +2), and (+2, ∞).

a. Interval (-∞, -2)

x < -2, so f'(x) > 0 when -∞ < x < -2

The function is increasing in (-∞, -2).

b. Interval (-2, 2)

|x| < 2, so f'(x) <0

The function is decreasing in (-2, 2).

c. Interval (2, ∞)

x > 2, so f'(x) > 0 when 2 < x < ∞

The function is increasing in (2, ∞).

Thus, the function is increasing in the intervals (-∞, -2) and (2, ∞).

8 0
3 years ago
If you need to write a do-while loop that will ask the user to enter a number between 2 and 5 inclusive, and will keep asking un
Iteru [2.4K]

Answer: (2 > number || number > 5)

Step-by-step explanation:

The do-while loop need to work until the user enters a correct number. In this case the number need to be between 2 and 5 inclusive.

On the opposite, if the user enters a number between 2 and 5 inclusive, he will leave the do-while loop.

Here is how it works : Once the user enters a number, the do-while loop will check this number.

If the number is NOT between 2 and 5 inclusive, the do-while loop will ask again the user to enter a number.

If the number is between 2 and 5 inclusive, the loop stop working.

So the do-while loop need to check if the number IS NOT between 2 and 5 inclusive.

If it is not between 2 and 5 inclusive, it could be :

Smaller than 2 : number < 2

Or greater than 5 = number > 5

The "or" condition is written by the symbols "||".

The loop condition is (2 > number || number > 5).

3 0
3 years ago
What are the coordinates of the midpoint of the line segment with endpoints 2,5 and 4,-7
Phoenix [80]
<h3>Answer:   (3, -1)</h3>

===============================================

Explanation:

The midpoint formula is (x_m, y_m) = \left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)

This basically says to add the corresponding coordinates and divide by 2.

The given points (2,5) and (4,-7) have x coordinates of 2 and 4. They add to 2+4 = 6, and then that result cuts in half to 6/2 = 3. The x coordinate of the midpoint is 3.

The y coordinate of the midpoint is y = -1 since adding the y coordinates of the given points leads to 5+(-7) = -2 which cuts in half to -1.

So overall the midpoint is located at (3, -1)

8 0
3 years ago
The population of Canyon Edge is 210,000, and the rate of population growth is 12.5%.
sergejj [24]
For this case we have a function of the form:
 y = A * (b) ^ x&#10;
 Where,
 A: initial population
 b: growth rate
 x: number of years.
 We then have the following function:
 y = 210000 * (1,125) ^ x&#10;
 For x = 4 years we have:
 y = 210000 * (1,125) ^ 4&#10;&#10; y = 336379
 Answer:
 
the formula for exponential growth is:
 
y = 210000 * (1,125) ^ x
 
The population of Canyon Edge after 4 years is:
 
y = 336379
3 0
4 years ago
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