Question

Find the magnitude of the vector (3, -6).Write your answer in simplified radical form.0/0 (0,0)X Х5?

Answer 1

$\begin{gathered} \vec{}v=\text{ (x,y)} \\ \lvert v\rvert=\sqrt[]{x^2+y^2\text{ }}\text{ this is the magnitud of a vector} \\ \text{the radical form is when you expess a number with his roots.} \\ \lvert v\rvert=\sqrt[]{3^2+(-6)^2} \\ \lvert v\rvert=\sqrt[]{9^{}+36} \\ \lvert v\rvert=\sqrt[]{45}\text{ but by law of the radicals can be simplified as follows } \\ \lvert v\rvert=\sqrt[]{5\cdot9}\text{ } \\ \lvert v\rvert=\sqrt[]{5^{}}\text{ }\sqrt[]{9}\text{ = 3 }\sqrt[]{5} \end{gathered}$