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Akimi4 [234]
1 year ago
7

Find the magnitude of the vector (3, -6).Write your answer in simplified radical form.0/0 (0,0)X Х5?

Mathematics
1 answer:
bekas [8.4K]1 year ago
8 0
\begin{gathered} \vec{}v=\text{ (x,y)} \\ \lvert v\rvert=\sqrt[]{x^2+y^2\text{ }}\text{ this is the magnitud of a vector} \\ \text{the radical form is when you expess a number with his roots.} \\ \lvert v\rvert=\sqrt[]{3^2+(-6)^2} \\ \lvert v\rvert=\sqrt[]{9^{}+36} \\ \lvert v\rvert=\sqrt[]{45}\text{ but by law of the radicals can be simplified as follows } \\ \lvert v\rvert=\sqrt[]{5\cdot9}\text{ } \\ \lvert v\rvert=\sqrt[]{5^{}}\text{ }\sqrt[]{9}\text{ = 3 }\sqrt[]{5} \end{gathered}

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Consider two medical tests, A and B for a virus. Test A is 90% effective at recognizing the virus when it is present, but has a
Licemer1 [7]

1

P(V|A) is not 0.95. It is opposite:

P(A|V)=0.95

From the text we can also conclude, that

P(A|∼V)=0.1

P(B|V)=0.9

P(B|∼V)=0.05

P(V)=0.01

P(∼V)=0.99

What you need to calculate and compare is P(V|A) and P(V|B)

P(V∩A)=P(A)⋅P(V|A)⇒P(V|A)=P(V∩A)P(A)

P(V∩A) means, that Joe has a virus and it is detected, so

P(V∩A)=P(V)⋅P(A|V)=0.01⋅0.95=0.0095

P(A) is sum of two options: "Joe has virus and it is detected" and "Joe has no virus, but it was mistakenly detected", therefore:

P(A)=P(V)⋅P(A|V)+P(∼V)⋅P(A|∼V)=0.01⋅0.95+0.99⋅0.1=0.1085

7 0
3 years ago
N is a positive integer
Murrr4er [49]

Part (1)

n is some positive integer. Let's say for now that n is even. So n = 2k, for some integer k

This means n-1 = 2k-1 is odd since subtracting 1 from an even number leads to an odd number.

Now multiply n with n-1 to get

n(n-1) = 2k(2k-1) = 2m

where m = k(2k-1) is an integer

The result 2m is even showing that n(n-1) is even

------------

Let's say that n is odd this time. That means n = 2k+1 for some integer k

And also n-1 = 2k+1-1 = 2k showing n-1 is even

Now multiply n and n-1

n(n-1) = (2k+1)(2k) = 2k(2k+1) = 2m

where m = k(2k+1) is an integer

We've shown that n(n-1) is even here as well.

------------

So overall, n(n-1) is even regardless if n is even or if n is odd.

Either n or n-1 will be even. If you multiply an even number with any number, the result will be even.

=======================================================

Part (2)

n is some positive integer

2n is always even since 2 is a factor of 2n

2n+1 is always odd because we're adding 1 to an even number. The sequence of integers goes even,odd,even,odd, etc and it does this forever.

-----------

Another way to see how 2n+1 is odd is to divide 2n+1 over 2 and you'll find that we get (2n+1)/2 = 2n/2+1/2 = n+0.5

The 0.5 at the end is not an integer, so there's no way that (2n+1)/2 is an integer; therefore 2n+1 is odd.

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2 years ago
Subtract u from 7, then divide v by the result
KatRina [158]
<span>Subtract u from 7, then divide v by the result</span>
v : (7 - u)
4 0
3 years ago
Please please help me solve
mash [69]
(2,4) is the only possible answer because it is the only one in the shaded area
5 0
3 years ago
Read 2 more answers
Given the line -2 + 2y = 5 , find the perpendicular line that goes through (1, -3). HeLP ME PLEASEE QUICK
brilliants [131]

Answer:

x=1

Step-by-step explanation:

Find the negative reciprocal of the slope of the original line and use the point-slope formula  y − y 1 = m ( x − x 1 )  to find the line perpendicular to  − 2 + 2 y = 5 .

4 0
3 years ago
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