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ludmilkaskok [199]
3 years ago
13

Plesssse help me with this

Mathematics
1 answer:
Wewaii [24]3 years ago
6 0
I think it’s the fourth one
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Q.Take out the area of the trapezium.<br>Parallel sides-15,23<br>Non parallel sides-10,8​
Dmitriy789 [7]

Answer:

Step-by-step explanation:

Area of a trapezium is the average of the parallel sides times the distance between them.

If we subtract 15 units from each of the parallel sides, we end up with a triangle that has two sides of 8 units and one of 10 units. One of the 8 unit sides is the base and we need to find the height h which is perpendicular to this base.

Let the base be split into two segments, call one A, the other will be 8 - A

From Pythagoras.

10² - A² = h² = 8² - (8 - A)²

10² - A² = 8² - (8 - A)²

100 - A² = 64 - (64 - 16A + A²)

100 - A² = 64 - 64 + 16A - A²

     100  =  16A

         A = 6.25

h = √(10² - 6.25²)

h = √60.9375  

A = ½(15 + 23)√60.9375  

A = 148.31870246... ≈ 148.3 cm²

3 0
3 years ago
Read 2 more answers
NEED HELP WITH THIS PROBLEM ASAP!!!!!!!
nata0808 [166]

Answer:

You're handwriting is good but i cant read itt

Step-by-step explanation:

4 0
3 years ago
5 rational numbers between 3.8 and 2 by 5
Alex

Answer:

Step-by-step explanation:

3.8=38/10=19/5

5 numbers between 19/5 and 2/5

=18/5,17/5,16/5,15/5,14/5

actually you can have infinite numbers between two numbers.

6 0
3 years ago
Find the third iterate, x3, of the function f(x) = 3x + 5 for an initial value of x0 = 1.
ratelena [41]
Find the third iterate, x3, of the function f(x) = 3x + 5 for an initial value of x0 = 1. <span>x1 = 3(1) + 5 = 8 ... x2 = 3(8) + 5 = 29 ... x3 = 3(29) + 5 = 92 </span>
4 0
3 years ago
What is <br>1/3(3x-6)^3+4&lt;13​
sesenic [268]

Answer:

x

Step-by-step explanation:

\frac{1}{3}(3x-6)^3+4

Solving the inequality to have solutions for x

Subtracting 4 from both sides.

⇒ \frac{1}{3}(3x-6)^3+4-4

⇒ \frac{1}{3}(3x-6)^3

Multiplying 3 both sides to remove fraction.

⇒ 3\times \frac{1}{3}(3x-6)^3

⇒ (3x-6)^3

Taking cube root both sides to remove the cube.

⇒ \sqrt[3]{(3x-6)^3}

⇒ (3x-6)                [ ∵ \sqrt[3]{27} =3 ]

Adding 6 to both sides.

⇒ 3x-6+6

⇒ 3x

Dividing both sides by 3

⇒ \frac{3x}{3}

∴ x

5 0
3 years ago
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