Answer:
See the attached figure which represents the problem.
As shown, AA₁ and BB₁ are the altitudes in acute △ABC.
△AA₁C is a right triangle at A₁
So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)
△BB₁C is a right triangle at B₁
So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)
From (1) and (2)
∴ A₁C/AC = B₁C/BC
using scissors method
∴ A₁C · BC = B₁C · AC
Answer:
it 12
i litterally just got it right so...
If the width is 28 inches, then divide that by 4 and you get 7. You multiply that by 5 to get the length. That would be 35. Just to check, you know that the width 28 and length 35 are in ratio 4:5 if you divide by 7. The perimeter would be 2(35+28)=63*2=126. So the perimeter is 126. The area would be 35*28 which is 980. To sum up, the answers are as follows.
Length: 35 in
Perimeter: 126 in
Area: 980 inches squared.
Answer:
the value of these two numbers are 1/2 and 3/2
Step-by-step explanation:
Given that:
x+y < 2 ---- (1)
y - x > 1 ---- (2)
From equation (2), let y > 1 + x then substitute it into equation (1)
x + 1 + x < 2
2x + 1 < 2
2x < 2 - 1
2x < 1
x < 1/2
From equation (2), replace the value of x to be 1/2
y - 1/2 > 1
y > 1 + 1/2
y > 3/2
5x-y
=5(3)-1
=15-1
=14
Therefore, the answer is 14.
