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1 year ago

9÷3+6×2³ffh ghutjujrhryry

Mathematics

1 answer:

givi [52]1 year ago

3 0

EXPLANATION:

Given the equation:

9/3 + 6x2^3

Solving the power:

9/3 + 6x8

Multiplying number:

9/3 + 48

Simplifying the fraction:

3 + 48

Adding numbers:

The answer is 51

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Find the value of x+1/x=3, then find x^3+1/x^3

spin [16.1K]

Answer:

x+1x=3x+1x=3

(x+1x)3=33(x+1x)3=33

x3+3.x2.1x+3.x.1x2+1x3=27x3+3.x2.1x+3.x.1x2+1x3=27

(x3+1x3)+3.x2.1x+3.x.1x2=27(x3+1x3)+3.x2.1x+3.x.1x2=27

x3+1x3+(3x+3x)=27x3+1x3+(3x+3x)=27

x3+1x3+3(x+1x)=27x3+1x3+3(x+1x)=27

x3+1x3+3×3=27x3+1x3+3×3=27

the answer is 18

4 0

3 years ago

Read 2 more answers

A standard deck of cards has 52 cards divided into 4 suits, each of which has 13 cards. Two of the suits ($\heartsuit$ and $\dia

Gnoma [55]

Answer:

The number of ways to select 2 cards from 52 cards without replacement is 1326.

The number of ways to select 2 cards from 52 cards in case the order is important is 2652.

Step-by-step explanation:

Combinations is a mathematical procedure to compute the number of ways in which k items can be selected from n different items without replacement and irrespective of the order.

${n\choose k}=\frac{n!}{k!(n-k)!}$

Permutation is a mathematical procedure to determine the number of arrangements of k items from n different items respective of the order of arrangement.

$^{n}P_{k}=\frac{n!}{(n-k)!}$

In this case we need to select two different cards from a pack of 52 cards.

Two cards are selected without replacement:

Compute the number of ways to select 2 cards from 52 cards without replacement as follows:

${n\choose k}=\frac{n!}{k!(n-k)!}$

${52\choose 2}=\frac{52!}{2!(52-2)!}$

$=\frac{52\times 51\times 50!}{2!\times50!}\\=1326$

Thus, the number of ways to select 2 cards from 52 cards without replacement is 1326.

Two cards are selected and the order matters.

Compute the number of ways to select 2 cards from 52 cards in case the order is important as follows:

$^{n}P_{k}=\frac{n!}{(n-k)!}$

$^{52}P_{2}=\frac{52!}{(52-2)!}$

$=\frac{52\times 51\times 52!}{50!}$

$=52\times 51\\=2652$

Thus, the number of ways to select 2 cards from 52 cards in case the order is important is 2652.

6 0

3 years ago

A company rents out 11 food booths and 22 game booths at the county fair. The fee for a food booth is $125 plus $6 per day. The

sattari [20]

Answer:

$3135 + $286d

Step-by-step explanation:

Given that:

Food booth = 11

Game booth = 22

Let number of days = d

Food booth rent = ($125 + 6d) * 11

Game booth rent = ($80 + 10d) * 22

Food booth = $1375 + $66d

Game booth = $1760 + $220d

Amount company is paid :

Food booth rent + game booth rent

($1375 + $66d) + ($1760 + $220d)

$(1375 + 1760) + $(66d + 220d)

$3135 + $286d

8 0

3 years ago

Similar statement of √111 Pls help

Diano4ka-milaya [45]

111 is between 11 and 12

7 0

3 years ago

Compute 5e2 - 4g + 7 where e = 4 and g = 6 ?

Elza [17]

The value of expression is 63 when e = 4 and g = 6

Solution:

Given expression is:

$5e^2-4g+7$

We have to solve the expression

Given that e = 4 and g = 6

Substitute e = 4 and g = 6 in given expression

$\rightarrow 5(4)^2 -4(6) + 7\\\\Simplify\ the\ above\ equation\\\\\rightarrow 5(16) -24 + 7\\\\\rightarrow 80-24+7\\\\Simplify\\\\\rightarrow 56+7=63$

Thus value of expression is 63

3 0

3 years ago