Answer:
b
Step-by-step explanation:
9x7.8x1/2x12
Circle equation
(x - h)^2 + (y - k)^2 = r^2
Since radius isn't given use the center and point, with the distance formula, to find the radius.
D=sqrt((x2-x2)^2+)y2-y1)^2)
D=sqrt((1-0)^2+(2-6)^2
D=sqrt(1+16)
D=sqrt 17
radius = sqrt 17
(h, k) is the center and r is the radius
(x - 1)^2 + (y - 2)^2 = 17
We have to find the number of ways an employer send 3 employees to a job fair if she has 11 employees.
This is the problem from combination.
The formula for combination is given by

Here, n= 11, r= 3
Therefore, total number of ways is given by

A is the correct option.
I think the answer is 12 because 3 times 4 is 12
Answer:

Step-by-step explanation:
We are given that
Height of man=5 foot

Height of street light=20ft
We have to find the rate of change of the length of his shadow when he is 25 ft form the street light.
ABE and CDE are similar triangle because all right triangles are similar.







Hence, the rate of change of the length of his shadow when he is 25 ft from the street light=