The width used for the car spaces are taken as a multiples of the width of
the compact car spaces.
Correct response:
- The store owners are incorrect
<h3 /><h3>Methods used to obtain the above response</h3>
Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.
We have;
Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)
New space design = 16·x + 9×(a·x) = x·(16 + 9·a)
When the dimensions of the initial and new arrangement are equal, we have;
10 + 12·a = 16 + 9·a
12·a - 9·a = 16 - 10 = 6
3·a = 6
a = 6 ÷ 3 = 2
a = 2
Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;
10 + 12·a < 16 + 9·a
Which gives;
x·(10 + 12·a) < x·(16 + 9·a)
Therefore;
The initial total car park space is less than the space required for 16
compact spaces and 9 full size spaces, therefore; the store owners are
incorrect.
Learn more about writing expressions here:
brainly.com/question/551090
Answer:
So if Charlie only has $27 to spend and hes already buying $3 kid's meal that leaves him with $24 to spend for 6 sandwiches. If you divide 6 by 24, 24/6 leaves him with $4 to spend on each sandwich.
Step-by-step explanation:
Sorry i really need points
Hello there, and thank you for posting your question here on brainly.
Short answer: C. 9
Why?
Box and whisker plots are confusing, the line in the middle is the median, but we don't need to do that now. The dots on the lines outside of the box show the largest and the shortest number. The plotted point on the way left is your answer, the line plotted is 9.
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