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7 months ago

5

-10=2x-4x how do you simplify this

1 answer:

ozzi7 months ago

5 0

The given formula is,

$-10=2x-4x$

Now solving for x,

$\begin{gathered} -10=-2x \\ x=\frac{-10}{-2}=5 \end{gathered}$

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Read 2 more answers

PLEASE HELP!<br><br> Reduce to simplest form.<br> 5/8 - (- 7/2)

Daniel [21]

Answer:

$\huge\boxed{\sf 4\frac{1}{8} }$

Step-by-step explanation:

$\sf =\frac{5}{8} - (-\frac{7}{2} )\\\\Rule : ( - *- = +)\\\\\=\frac{5}{8} +\frac{7}{2} \\\\LCM = 8\\\\\=\frac{5+28}{8} \\\\\=\frac{33}{8} \\\\=4\frac{1}{8}$

$\sf =\frac{5}{8}+ \frac{7}{2} \\\\=\frac{5+28}{8}$

$\sf =\frac{33}{8} \\\\=4\frac{1}{8}$

Hope this helped!

<h2>~AnonymousHelper1807</h2>

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2 years ago

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2 years ago

Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:

ryzh [129]

First find the critical points of <em>f</em> :

$f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7$

$\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1$

$\dfrac{\partial f}{\partial y}=6y=0\implies y=0$

so the point (1, 0) is the only critical point, at which we have

$f(1,0)=-7$

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

$f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t$

Find the critical points of <em>g</em> :

$\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0$

$\implies\sin t=0\text{ OR }1+5\cos t=0$

$\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi$

where <em>n</em> is any integer. We get 4 critical points in the interval [0, 2π) at

$t=0\implies f(10,0)=155$

$t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299$

$t=\pi\implies f(-10,0)=235$

$t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299$

So <em>f</em> has a minimum of -7 and a maximum of 299.

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3 years ago