Answer:
80 lb of salt
Step-by-step explanation:
Let us assume the water flows into the rank for x minutes.
There is an initial of 60 gallons of water in the tank and water flows in at 3 gal/min. In x minute, the amount of water in the tank = 60 + 3x
Water flows out at 1 gal/min, therefore in x minute the amount of water in the tank = 60 + 3x - x = 60 + 2x
The tank begins to overflow when it is full (has reached 130 gallons). Therefore:
130 = 60 + 2x
2x = 130 - 60
2x = 70
x = 35 minutes.
In 35 minutes the tank would start to overflow.
1 lb salt per gallon flows into the tank at 3 gal/min, in 35 min the amount of salt that entered the tank = 3 gal/min × 35 min × 1 lb/gal = 105 lb
1 lb salt per gallon flows out of the tank at 1 gal/min, in 35 min the amount of salt that flow out of the tank = 1 gal/min × 35 min × 1 lb/gal = 35 lb
Initially there is 10 lb of salt dissloved into 60 gallons of water.
Therefore the amount of salt is in the tank when it is about to overflow = 10 + 105 - 35 = 80 lb of salt.
Answer:
-5 because with 0,0 you are not subtracting anything so it would stay the same
Answer:
703.7cm²
Step-by-step explanation:
Since we must not count the top and bottom 2cm,
- The height of the label is (20-2-2) = 20 - 4 = 16cm
- Finding the curved surface area of a cylinder: 2πrh
where r = radius and h = height.
- Since the diameter is 14cm, the radius is 14/2 = 7cm
- Substituting 'r=7' & 'h=16' into the curved surface area of a cylinder formula:
2π(7)(16)
= (14)(16)π
= 224π
= 703.716754404cm²
≈ 703.7cm²
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Answer:
x = 0
Step-by-step explanation:
The axis of the symmetry has the same x coordinate of the vertex
V (x) = -b/2a
in both equations b is equal to 0 and a 0/a number different from 0 gives always 0 as a result