Answer:
Figure 3
Figure 1
Step-by-step explanation:
Figure 1 is the pre-image
The side length is 2. We multiply the side length by the scale factor.
2 * 4 = 8
The new figure will have a side length of 8. That will be Figure 3
Figure 2 is the pre-image
The side length is 4. We multiply the side length by the scale factor.
4 * 1/2 = 2
The new figure will have a side length of 2. That will be Figure 1
Answer:
a. 60 minutes in one hour.
b. 3,600 seconds in one hour.
c. 1,440 minutes in one day.
d. 86,400 seconds in one day.
e. 10,080 minutes in one week. 604,800 seconds in one week.
Answer:
1156528
Step-by-step explanation:
you multiply all of the numbers to get it i think hope this helps
Answer:
The graph in (A)
Step-by-step explanation:
Negative discriminant of a quadratic function implies the corresponding quadratic equation ax^2+bx+c=0 does not have any real solutions (it still has solutions in the complex domain, however). Graphically, this corresponds to a parabola that never intersects the x axis for any value x, i.e. it lies either fully above or fully below the x axis. This situation is depicted in the case (A), where the parabola lies below the x axis and has no x-intercepts.
The cases (B), (C), and (D) all intersect the x axis in at least one point.
We know that sin(pi/6) = 1/2 and cos(pi/3) = 1/2. So arcsin and arccos is defined for x=1/2.
Now csc x = 1/sin x and sec x = 1/cos x.
So if csc x = 1/2, then sin x = 2, which is not in its domain. Same argument applies for sec x. You could think of this in terms of the graph too.
For arctan(x) and arccot(x), think of the graph. It is continuous everywhere and defined. Now one strategy you could use if you do not know of its graph is taking the graph of tan(x) and cot(x), restrict its domain and reflect it to obtain arctan(x) and arccot(x).