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Degger [83]
3 years ago
15

A company has determined that its weekly profit is a function of the number of items that it sells. Which equation could

Mathematics
2 answers:
CaHeK987 [17]3 years ago
7 0
<h3>The needed equation representing the profit y is represented in the option B.</h3><h3>B. y  = -x² + 50 x - 300 </h3>

Step-by-step explanation:

Here, the given options are incomplete.

A. y²  = 4 x²  - 100

B. y  = -x² + 50 x - 300

C.  x =  -y² + 60 y - 400

D. x ²  =  - 6 y² + 200

The number of items sold by the company  = x

The profit ( in thousands) is represented as  = y

Now, here as we are looking for the equation representing profit (y)

So, we can disregard the equations which has terms (x)  and ( x²)  in left.

⇒The equations in the options C and D are eliminated.

Similarly, again we are looking for the equation for Profit , not (profit)².

So,we can disregard the equation which has terms (y²)  in left side.

⇒The equation in the options A is eliminated.

Hence, the needed equation representing the profit y is represented in the option B.

B. y  = -x² + 50 x - 300

dalvyx [7]3 years ago
3 0

Answer: B

Step-by-step explanation:

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The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. Th
finlep [7]

Question:

The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. The top one is labeled Class. Minimum at 70, Q1 at 74, median at 83, Q3 at 92, maximum at 100. The bottom box plot is labeled Exam. Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95. Which of the following best describes the information about the medians? (1 point) Group of answer choices

•The exam outlier at 60 makes the IQR narrower and the median higher.

•The class data is more evenly spread, which pulls its median down.

•The class median is lower than the exam median.

•The class Q3 is higher than the exam Q3.

Answer:

•The class Q3 is higher than the exam Q3.

Step-by-step explanation:

In the question we have two box plots

a) Box plots for class is given as

Minimum at 70, Q1 at 74, median at 83, Q3 at 92,

b) Box plots for exam is given as Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95.

When we compare the median of the class which is 83 and the median of the exam plots 87, we can see that the median of the exam is higher than the median of the class, hence the option

"•The class median is lower than the exam median". is wrong.

From the options given, the only correct option which best describes the information about the medians is

"•The class Q3 is higher than the exam Q3".

This is because when we compare the Q3 of the class which is 92 to the Q3 of the box which is 91 , we can see that the class Q3 is higher than the box Q3 hence the option is correct.

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3 years ago
To three decimal places, find the average value of f(x) = 2x2 + 3 on the interval [0, 2].
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3 years ago
Identify the vertical asymptotes of f(x) = 2 over quantity x squared plus 3 x minus 10.
zysi [14]
The function is:
f ( x ) = 2 / ( x² + 3 x - 10 )
x² + 3 x - 10 = x² + 5 x - 2 x - 10 = x ( x + 5 ) - 2 ( x + 5 ) =
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x - 2 = 0 => x = 2
Answer:
The vertical asymptotes are: x = - 5 and x = 2.
3 0
2 years ago
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