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1 year ago

Put them in order from least to greatest: 2.5 6.7 6.9 7.5 1.8 1.6

Mathematics

2 answers:

stira [4]1 year ago

7 0

Step-by-step explanation:

1.6 1.8 2.5 6.7 6.9 7.5

was that really all ? I don't see any trap in these numbers, so this is straight forward.

vladimir2022 [97]1 year ago

4 0

Answer: 1.6,1.8,2.5,6.7,6.9,7.5

Step-by-step explanation:

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How do you do this problem

Ainat [17]

So the problem has no symbols, but we're going to multiply because the fraction on the left is right next to the parentheses.

-5/2 * 1/10x = -5x/20

I put "x" next to the 5 because the "x" counts as part of the numerator. Now that it's 5x over 20 that equals one, I'd first reduce -5x/20 into -x/4, then do

-x/4 * -4 = 1 * -4

To make the "x" side equal one, we have to multiply both sides by -4, to make both sides equal.

x = -4.

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2 years ago

Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili

lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

B = bugs are present in a computer program.

D = a de-bugging program detects the bug.

The information provided is:

$P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02$

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event E given that another event X has already occurred is:

$P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}$

Use the Bayes' theorem to compute the value of P (B | D) as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333$

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

$=0.3333\times 0.3333\\=0.11108889\\\approx 0.1111$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

$=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

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3 years ago

Find the range of the line

navik [9.2K]

Answer:

(-10,3),(9,0)

Step-by-step explanation:

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3 years ago

Which of the following is the least? A. 0.105 B. 0.501 C. 0.015 D. 0.15

Naddika [18.5K]

C is the least that is beause it is .015 which is smaller than 0.15

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2 years ago

Jan is saving for a skateboard. She save $30 already which is 20% of the total price. How much does skateboard cost

Stolb23 [73]

The skateboard cost $150

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3 years ago