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3 years ago

Can anyone solve this ?

Mathematics

1 answer:

enot [183]3 years ago

6 0

Is e just an algebraic expression or is it Euler's number (2.718...)?

If e is an algebraic expression then there it is

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lisa is painting a fence that is 26 feet long and 7 feet tall. a gallon of paint will cover 350 aquare feet. write and slove a p

vaieri [72.5K]

The fence is 26*7=182 square feet. 1 gallon is enough for 350 square feet and x for 182 square feet. => x=182/350=0.52 gallons. I hope I'm right.

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3 years ago

What is the solution to these equations y= 2x +1 and x +2y= 27

Llana [10]

Answer:

The first one is -1/2

the second one is x+2y-27=0

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3 years ago

Which point represents the approximate location of 388 squared

Phoenix [80]

Answer:

Point D

$\sqrt{388} = 19.7 \\ between \: 19 \: and \: 20$

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3 years ago

Wanda is eating breakfast at fifteen minites before eight what time is this use a.m or p.m

makvit [3.9K]

It would be 7:45 am. Am because she's eating breakfast and 7:45 plus 15 is 8

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3 years ago

Read 2 more answers

Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to

RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

5 0

3 years ago