1 year ago

select the correct answer from the drop-down menufind the polynomial(5) is the solution set of ___A. X^2-5x + 25=0B. X^2 + 10x +

25 = 0C. X^2-10x+25=0D. X^2+5x+25=0

1 answer:

7 0

$\begin{gathered} (x+5)^2=x^2+2(x)(5)+(5)^2 \\ (x+5)^2=x^2+10x+25 \\ \\ (x-5)^2=x^2+2(x)(-5)+(-5)^2 \\ (x+5)^2=x^2-10x+25 \end{gathered}$

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Mumz [18]

Answer:

n = 5

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Coordinate of P = (n,3)

R is on y-axis & the y-coordinate of P & R are equal. So coordinate of R = (3,0)

Coordinate of Q = (n,-2)

Using distance formula,

Distance between P & Q =

$\sqrt{ {( n - n}) ^{2} + {( 3- ( - 2) })^{2} }$

$= > \sqrt{ {(3 + 2)}^{2} } = \sqrt{ {5}^{2} } = 5$

Distance between P & R =

$\sqrt{ {(n - 0)}^{2} + {(3 - 3)}^{2} }$

$= > \sqrt{ {n}^{2} } = n$

But in question it is given that distance between P & Q is equal to the distance between P & R. So,

$n = 5$

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