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Rashid [163]
1 year ago
5

select the correct answer from the drop-down menufind the polynomial(5) is the solution set of ___A. X^2-5x + 25=0B. X^2 + 10x +

25 = 0C. X^2-10x+25=0D. X^2+5x+25=0
Mathematics
1 answer:
postnew [5]1 year ago
7 0
\begin{gathered} (x+5)^2=x^2+2(x)(5)+(5)^2 \\ (x+5)^2=x^2+10x+25 \\  \\ (x-5)^2=x^2+2(x)(-5)+(-5)^2 \\ (x+5)^2=x^2-10x+25 \end{gathered}

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3 years ago
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X-5(x-1)=2x-(2x-3) answer the question
levacccp [35]

Answer: x= 1/2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

x−5(x−1)=2x−(2x−3)

x−5(x−1)=2x+−1(2x−3)(Distribute the Negative Sign)

x−5(x−1)=2x+−1(2x)+(−1)(−3)

x−5(x−1)=2x+−2x+3

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x+−5x+5=2x+−2x+3

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Step 2: Subtract 5 from both sides.

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Step 3: Divide both sides by -4.

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natka813 [3]
Sure this question comes with a set of answer choices.

Anyhow, I can help you by determining one equation that can be solved to determine the value of a in the equation.

Since, the two zeros are - 4 and 2, you know that the equation can be factored as the product of (x + 4) and ( x - 2) times a constant.  This is, the equation has the form:

y = a(x + 4)(x - 2)

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10 = a (10)(4)

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