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Lesechka [4]
3 years ago
15

If somebody can give me the answer!!! Please I need help

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
7 0
B is the correct answer
adoni [48]3 years ago
3 0

Answer:

Its B

Step-by-step explanation:

You're correct

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Rewrite (120 + 20) using factoring.
solong [7]

5(24+4) Also 20(6+1)...................

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2 years ago
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8. A right cone has a volume of 8,579 m3 and a radius of 16 m. Find its altitude.
Monica [59]

Answer:

Option A is correct.

Step-by-step explanation:

The formula used for finding the volume of right cone is:

Volume of Right cone = (1/3)π.r².h

We need to find altitude i.e h

Volume of cone=V = 8579 m^3

Radius=r = 16m

Altitude =h =?

Putting values,

8579 = (1/3) * 3.14 * (16)^2*h

8579 = 1/3 * 3.14 * 256 *h

8579 = 267.95 * h

=> h = 8579/267.95

h = 32.0 m

So, Altitude of right cone is 32.0 m

Option A is correct.

4 0
4 years ago
Which graph represents a function with direct variation?<br><br>​
sweet [91]

This is easier than you think!

When a graph shows direct variation, it always <em>passes through the origin</em>

The origin is (0, 0)

The very <u>center! </u>

Your answer is the first graph!

5 0
3 years ago
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A building has a height of 100ft and a length of 100ft. An architect wants to add to the building by doubling the length of the
skelet666 [1.2K]
That would be 200ft sir
5 0
4 years ago
There are 20 machines in a factory. 7 of the machines are defective.
adelina 88 [10]

Answer:

0.1225

Step-by-step explanation:

Given

Number of Machines = 20

Defective Machines = 7

Required

Probability that two selected (with replacement) are defective.

The first step is to define an event that a machine will be defective.

Let M represent the selected machine sis defective.

P(M) = 7/20

Provided that the two selected machines are replaced;

The probability is calculated as thus

P(Both) = P(First Defect) * P(Second Defect)

From tge question, we understand that each selection is replaced before another selection is made.

This means that the probability of first selection and the probability of second selection are independent.

And as such;

P(First Defect) = P (Second Defect) = P(M) = 7/20

So;

P(Both) = P(First Defect) * P(Second Defect)

PBoth) = 7/20 * 7/20

P(Both) = 49/400

P(Both) = 0.1225

Hence, the probability that both choices will be defective machines is 0.1225

4 0
3 years ago
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