So, f[x] = 1/4x^2 - 1/2Ln(x)
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
Answer:
a₁ = -21 (Given)
a₂ = -28
a₃ = -35
a₄ = -42
Step-by-step explanation:
First term a₁ = -21 (Given)
…………………………………
Second term a₂ :
a₂ = 
…………………………………
Third term a₃ :
a₃ = 
…………………………………
Fourth term a₄ :
a₄ = 
0.59 and 2/3
0.59
0.66
0.59 < 2/3
2/3 is greater than 0.59.
Answer :
Answer:
angle DFG = 49 degrees
angle JKL = 41 degrees
Step-by-step explanation:
When angles are complementary with each other, it means that if you add both of the angles up, it adds up to 90 degrees.
In this question, you would have to add up angle DFG and angle JKL and find the x that makes the equation equal to 90 degrees.
angle DFG = x + 5
angle JKL = x - 3
(x + 5) + (x - 3) = 90
2x + 2 = 90
2x = 90 - 2
2x = 88
x = 44
But since we have to find out the angle measures, we have to the "x = 44" with the x's in the DFG and JKL angles.
DFG = (44) + 5 = 49
JKL = (44) - 3 = 41
Answer:
Coordinates of the midpoint are (-5.5, 5)
