1.A.
The base lengths of the trapezoid are 35cm and 19cm. The height is 15cm.
1.B.
The formula for the area of a trapezoid is
A=(b1+b2)/2*h
plug in the data we know
A=(35+19)/2*15
A=54/2*15
A=27*15
A=405cm²
since there are two trapezoids, we double that number 405*2=810cm²
Answer=810cm²
1.C.
To solve for this, we need to find the perimeter of the trapezoid
P=35+19+17+17=88cm
Answer=No. The edges of the trapezoid are longer than 80cm.
2.A.
3units. Since their x values are the same, you just subtract the y values to calculate distance 5-2=3
Answer=3
2.B
A right triangle. Since one coordinate is directly above, and the other is directly to the right of the bench
3.A
The two triangles would be...
A=1/2b*h=1/2*30*72=15*72=1080ft² each
and the center rectangle would be
A=l*w=20*72=1440ft²
Add them all together and you get
Total area=3600ft²
Answer:
Step-by-step explanation:
5y - 2y = 10
3y = 10
y = 10/3 = 3⅓
Answer:
Step-by-step explanation:
x:14 = 6:24 ovvero x =14*6/24 =3,5 piedi metri 1,0668
Your friend is incorrect:
10/3 = 3.33
3/10 = 0.3
Let x=number 1 let y=number2
there sum is equal to 70
then
number1+number2=70
substituting
x+y=70
y=70-x
let there product will be p
p=xy
substituting
p=x(70-x)
which is choice c
