2 years ago

I need help please help

1 answer:

6 0

A. pat x-10 is a negative

You might be interested in

Alexus [3.1K]

4 colour needed for this…i think

8 0

1 year ago

Sophie [7]

The idea is to use the tangent line to $f(x)=\sqrt x$ at $x=25$ in order to approximate $f(25.3)=\sqrt{25.3}$ .

We have

$f(x)=\sqrt x\implies f(25)=\sqrt{25}=5$

$f'(x)=\dfrac1{2\sqrt x}\implies f'(25)=\dfrac1{10}$

so the linear approximation to $f(x)$ is

$L(x)=f(5)+f'(5)(x-5)=5+\dfrac{x-5}{10}=\dfrac x{10}+\dfrac92$

Hence $m=\frac1{10}$ and $b=\frac92$ .

Then

$f(25.3)\approx L(25.3)=\dfrac{25.3}{10}+\dfrac92=\boxed{7.03}$

4 0

2 years ago

densk [106]

Answer:

1.85

Step-by-step explanation:

4 0

1 year ago

kolezko [41]

Answer:

The inequality for this would be n ≥ 20.

We know this because it must be larger than 40. We also know it can possibly be equal because the statement says "at least".

Step-by-step explanation:

6 0

1 year ago

AfilCa [17]

22 kilometers :) hope that helped

3 0

2 years ago