Question

Factor out the following by taking out the GCF18cd^2+12c^2d+9cd

Answer 1

The given polynomial is:

$18cd^2+12c^2d+9cd$

The first step to factor taking out the GCF is to write each term in prime factored form, so:

$\begin{gathered} 18cd^2=2\times3\times3\times c\times d\times d \\ 12c^2d=2\times2\times3\times c\times c\times d \\ 9cd=3\times3\times c\times d \end{gathered}$

The second step is to identify the factors common in all terms, they are: 3xcxd

Finally, factor out the GCF:

$3cd(6d+4c+3)$

The answer is above