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m_a_m_a [10]
2 years ago
10

Ms. Gonzales gathered data on the number of vowels in the first and last names of each of her students. The data are shown in th

e dot plot.
Vowels in student names. Number of vowels.

What percentage of the students have 5 or more vowels in their first and last names?
Mathematics
1 answer:
Svetllana [295]2 years ago
7 0
Where s the data of the students
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A​ half-century ago, the mean height of women in a particular country in their 20s was 64.7 inches. Assume that the heights of​
Ainat [17]

Answer:

99.5% of all samples of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches.

Step-by-step explanation:

We are given that a half-century ago, the mean height of women in a particular country in their 20's was 64.7 inches. Assume that the heights of​ today's women in their 20's are approximately normally distributed with a standard deviation of 2.07 inches.

Also, a samples of 21 of​ today's women in their 20's have been taken.

<u><em /></u>

<u><em>Let </em></u>\bar X<u><em> = sample mean heights</em></u>

The z-score probability distribution for sample mean is given by;

                          Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean height of women = 64.7 inches

            \sigma = standard deviation = 2.07 inches

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches is given by = P(\bar X \geq 65.86 inches)

  P(\bar X \geq 65.86 inches) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{65.86-64.7}{\frac{2.07}{\sqrt{21} } } ) = P(Z \geq -2.57) = P(Z \leq 2.57)

                                                                        = <u>0.99492  or  99.5%</u>

<em>The above probability is calculated by looking at the value of x = 2.57 in the z table which has an area of 0.99492.</em>

<em />

Therefore, 99.5% of all samples of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches.

3 0
3 years ago
6/30=3/15 true or false
Dennis_Churaev [7]

Answer: True

Step-by-step explanation: This is because they are equivalent fractions

Hope this helps and have a nice day

4 0
3 years ago
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Dylan is evaluating the expression 13 + 19 + 7 + 10. At one step in his work, Dylan rewrites the equation as 13 + 7 + 19 + 10. W
musickatia [10]

Answer:

1

Step-by-step explanation:

i am not sure but that is what i got.

7 0
3 years ago
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HELP! Giving branliest to who answers!!!
WARRIOR [948]

Answer: A. -1.8

Step-by-step explanation: Hi there!

First, we have to see the constant rate of change in the x and y values.

For x: 2

For y: -3.6

If the slope is m=y/x

then we can do

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that simplifies to

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which is

-1.8

Hope this answer helps you!

4 0
3 years ago
30 POINTS
lesantik [10]

Answer: (26996, 42744)

Step-by-step explanation: N/A

5 0
3 years ago
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