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RideAnS [48]
9 months ago
13

2 1/2x + 1/4 + 3/4x = 1/8

Mathematics
1 answer:
Vinil7 [7]9 months ago
6 0

\frac{5}{2}x+\frac{1}{4}  +\frac{3}{4} x=\frac{1}{8} \\\\\frac{5}{2}(8)x+\frac{1}{4}  (8)+\frac{3}{4}(8) x=\frac{1}{8}(8)\\20x+2+6x=1\\20x+6x=1-2\\26x=-1\\\frac{26x}{26} =\frac{-1}{26} \\x=-\frac{1}{26}

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Simplify (-2x^4y^-3)^4
elixir [45]

Answer:

( - 2 {x}^{4} {y}^{ - 3} )^{4}  =  \frac{16 {x}^{16}}{ {y}^{12} }

Step-by-step explanation:

We want to simplify:

( - 2 {x}^{4} {y}^{ - 3} )^{4}

We need to apply the exponential property for products of powers.

Recall that:

( {a}^{m}  \times  {a}^{n} )^{p}  =  {a}^{mp}  \times  {a}^{np}

We apply this rule to get:

( - 2 {x}^{4} {y}^{ - 3} )^{4}  = ( { - 2)}^{4} x \times {x}^{16}  \times {y}^{ - 12}

This simplifies to:

( - 2 {x}^{4} {y}^{ - 3} )^{4}  = 16 {x}^{16}  \times {y}^{ - 12}

We rewrite as positive index to get:

( - 2 {x}^{4} {y}^{ - 3} )^{4}  =  \frac{16 {x}^{16}}{ {y}^{12} }

7 0
3 years ago
An automobile manufacturer is preparing a shipment of cars and trucks on a cargo ship that can carry 21,600 Tons. The cars weigh
inysia [295]

Answer:

Number of trucks (y) that can be shipped if the number of cars (x) is known=\frac{21,600-3.6x}{7.5}

Step-by-step explanation:

A cargo ship can carry 21,600 Tons.

Let x denotes number of cars and y denotes number of trucks.

The cars weigh 3.6 tons each and the trucks weigh 7.5 tons each.

Therefore,

3.6x+7.5y=21,600

Now write y in terms of x.

7.5y=21,600-3.6x\\y=\frac{21,600-3.6x}{7.5}

Number of trucks (y) that can be shipped if the number of cars (x) is known=\frac{21,600-3.6x}{7.5}

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Answer:

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area is 530.93

Step-by-step explanation:

C=2πr=2·π·13≈81.68141

A=πr2=π·132≈530.92916

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Step-by-step explanation:

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3 years ago
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zlopas [31]
5/6 + 3/8

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Convert to mixed number:

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