Answer:
perpendicular line through a point on a line
Step-by-step explanation:
The circle centered at C seems intended to produce point D at the same distance as point B. That is, C is the midpoint of BD.
The circles centered at B and D with radius greater than BC seems intended to produce intersection points G and H. (It appears accidental that those points are also on circle C. As a rule, that would be difficult to do in one pass.)
So. points G and H are both equidistant from points B and D. A line between them will intersect point C at right angles to AB.
Segment GH is perpendicular to AB through point C (on AB).
Answer:
y - 4 = 3(x- (-1) ---> y-4 = 3(x+1)
Step-by-step explanation:
y - 4 = 3(x + 1)
y - 4 = 3x + 3
y = 3x + 7
then plug in (-1,4)
4 = 3(-1) + 7
4 = -3 + 7
4 = 4
Point slope form looks like:
y - y₁ = m(x - x₁)
Step 1
<u>Find the value of TS</u>
we know that
if PQ is parallel to RS. then triangles TRS and TPQ are similar
so
solve for TS
we have
substitute
Step 2
<u>Find the value of SQ</u>
we know that
we have
substitute
therefore
<u>the answer is</u>
the value of SQ is 
Answer:
12:50 PM.
Step-by-step explanation:
We have been given that Craig’s school has 4 lessons in the morning and lesson 1 starts at 8:35. Each lesson is 60 minutes long. There is a break of 15 minutes between lesson 2 and 3.
We can see that lesson 1 will end at 9:35 AM and second lesson will end at 10:35 AM.
We have been also given that there is a break for 15 minutes between lesson 2 and 3. So third lesson will start at 10:50 AM as lunch break will end at 10:50 AM.
Third lesson will end 60 minutes after 10:50 AM that is 11:50 AM and fourth lesson will end 60 minutes after 11:50 AM that is 12:50 PM.
Therefore, 4th lesson will end at 12:50 PM.
The solution to a system of equations is the point where the 2 lines of a graph cross each other.
On the pictured graph, the lines cross each other at x = -6 and Y = -2.
The answer would be (-6,-2)
