4 and 1
3 and 2
im pretty sure thats is the answer, the question is quite vague.
Answer:
0.665
Step-by-step explanation:
Given: 100 people are split into two groups 70 and 30. I group is given cough syrup treatment but second group did not.
Prob for a person to be in the cough medication group = 0.70
Out of people who received medication, 34% did not have cough
Prob for a person to be in cough medication and did not have cough
=
Prob for a person to be not in cough medication and did not have cough
=
Probability for a person not to have cough
= P(M1C')+P(M2C')
where M1 = event of having medication and M2 = not having medication and C' not having cough
This is because M1 and M2 are mutually exclusive and exhaustive
SO P(C') = 0.397+0.2=0.597
Hence required prob =P(M1/C') = 
Answer:
x= 9, x= 2
Step-by-step explanation:
x^2- 2x- 9x+ 18= 0
x (x-2) -9 (x-2)
(x-9) (x-2)
x-9= 0, x-2= 0
Therefore, x= 9, x= 2
If you don't mind, plz mark me brainliest
Answer:
thanks if u need help let me know
Step-by-step explanation: