Answer:
P = 58.52 atm
Explanation:
Given data:
Mass of sample = 32.0 g
Pressure of sample = ?
Volume of gas = 850 cm³
Temperature of gas = 30°C
Solution:
Number of moles of gas:
Number of moles = mass/molar mass
Number of moles = 32.0 g/ 16 g/mol
Number of moles = 2 mol
Pressure of gas:
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
30+273 = 303 K
850 cm³ × 1L /1000 cm³ = 0.85 L
by putting values,
P× 0.85 L = 2 mol × 0.0821 atm.L/ mol.K × 303 K
P = 49.75 atm.L/ 0.85 L
P = 58.52 atm
Is there any answer so I can answer it
The answer to the problem is
69.55
Magnesium potassium phosphate hexahydrate and a number of its deuterated counterparts were studied for their Fourier transform infrared and Raman spectra. By contrasting the spectra obtained at the boiling point of liquid nitrogen with those obtained at ambient temperature and by examining the spectra of a succession of partially deuterated MgKPO4
<h3>What is Infrared and raman spectroscopy ?</h3>
Raman and infrared spectroscopy both investigate how radiation interacts with molecular vibrations, but they do so in different ways depending on how the photon energy is delivered to the molecule by altering its vibrational state.
- While IR spectroscopy depends on a change in the dipole moment, Raman spectroscopy depends on a change in the polarizability of a molecule. In contrast to IR spectroscopy, which measures the absolute frequencies at which a sample absorbs light, Raman spectroscopy measures the relative frequencies at which a sample scatters light.
Learn more about Spectroscopy here
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