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MrMuchimi
3 years ago
10

Which changes occur when Pt2+ is reduced?

Chemistry
2 answers:
Tomtit [17]3 years ago
6 0

Answer: Option (2) is the correct answer.

Explanation:

When an element or compound gain electrons then this means the element is undergoing reduction.

Also, in reduction oxidation number of the element decreases.

For example, Pt^{2+} + 1e^{-} \rightarrow Pt^{+1}

Thus, we can conclude that the Pt^{2+} gains electrons and its oxidation number decreases.

skad [1K]3 years ago
3 0
The correct answer is option 2. When Pt2+ is reduced it loses electrons, oxidizing it. The oxidation number is the charge of the atom. Adding an electron, decreases the net charge consequently the oxidation number.
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What is the lightest material ever created by the hands of men
lutik1710 [3]
The world's lightest material is carbon aerogel which has a mass of only 0.16 milligram and it is even lighter than aerographite.
6 0
3 years ago
How many phase rule variables must be specified to fix the thermodynamic state of each of the following systems? Show how you de
Murrr4er [49]

Answer: (i) F = 2

(ii) F = 3

(iii) F = 2

Explanation:

We would be applying the famous Gibbs Phase Rule to explaining this problem;

By applying the formula;

F+P = C +2

Where P = this represent the phase

F = this is called the degree of freedom

C = this represent the component in the system

Ok let us begin;

(i). from this we can see that there are 2 components i.e. (water + ethanol) and the phase in question is a vapor phase + liquid phase.

So from the formula;

F = C-P+2

F = 2 – 2 + 2 = 2

Therefore, F = 2.

(ii). Also, from the statement, we can figure there are 3 components, while the phases are two like the previous one above, i.e. liquid + vapor

F = 3 – 2 + 2 = 5 – 2 = 3

F = 3

(iii). From this statement, we can figure there are 3 components, and the phases are 3 i.e. (2 liquid phases + 1 vapor phase)

From the formula;

F = 3 – 3 + 2 = 0 + 2

F = 2

6 0
3 years ago
12. Chubchub runs a 440m lap in 1.2 minutes. How many laps will Chubchub
Svet_ta [14]

Answer:

the  number of laps in the case when he run for 50 minutes is 18,333.33

Explanation:

The computation of the number of laps in the case when he run for 50 minutes is shown below:

Given that

He runs 440m lap in 1.2 minutes

So in 50 minutes he can have laps of

= 440 × 50 ÷ 1.2

= 18,333.33 laps

hence, the  number of laps in the case when he run for 50 minutes is 18,333.33

3 0
3 years ago
How many moles of a gas would occupy 22.4 Liters at 273 K and 1 atm?
Molodets [167]

Answer:

1 mole of a gas would occupy 22.4 Liters at 273 K and 1 atm

Explanation:

An ideal gas is a set of atoms or molecules that move freely without interactions. The pressure exerted by the gas is due to the collisions of the molecules with the walls of the container. The ideal gas behavior is at low pressures, that is, at the limit of zero density. At high pressures the molecules interact and intermolecular forces cause the gas to deviate from ideality.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

In this case:

  • P= 1 atm
  • V= 22.4 L
  • n= ?
  • R= 0.082 \frac{atm*L}{mol*K}
  • T=273 K

Reemplacing:

1 atm* 22.4 L= n* 0.082 \frac{atm*L}{mol*K} *273 K

Solving:

n=\frac{1 atm* 22.4 L}{0.082 \frac{atm*L}{mol*K} *273 K}

n= 1 mol

Another way to get the same result is by taking the STP conditions into account.

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C (or 273 K) are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

<u><em>1 mole of a gas would occupy 22.4 Liters at 273 K and 1 atm</em></u>

4 0
2 years ago
Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction free energy of the following chemical
julia-pushkina [17]

Answer:

43.0 kJ

Explanation:

The free energy (ΔG) measures the total energy that is presented in a thermodynamic system that is available to produce useful work, especially at thermal machines. In a reaction, the value of the variation of it indicates if the process is spontaneous or nonspontaneous because the free energy intends to decrease, so, if ΔG < 0, the reaction is spontaneous.

The standard value is measured at 25°C, 298 K, and the value of free energy varies with the temperature. It can be calculated by the standard-free energy of formation (G°f), and will be:

ΔG = ∑n*G°f products - ∑n*G°f reactants, where n is the coefficient of the substance in the balanced reaction.

By the balanced reaction given:

2NOCl(g) --> 2NO(g) + Cl2(g)

At ALEKS Data tab:

G°f, NOCl(g) = 66.1 kJ/mol

G°f, NO(g) = 87.6 kJ/mol

G°f, Cl2(g) = 0 kJ/mol

ΔG = 2*87.6 - 2*66.1

ΔG = 43.0 kJ

6 0
3 years ago
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