Answer:
The mass of the precipitate  that AgCl is 3.5803 g.
Explanation:
a) To calculate the molarity of solution, we use the equation:

We are given:
Mass of solute (NaCl) = 1.46 g
Molar mass of sulfuric acid = 58.5 g/mol
Volume of solution = 

Putting values in above equation, we get:

0.09982 M is the concentration of the sodium chloride solution.
b) 
Moles of NaCl = 
according to reaction 1 mol of NaCl gives 1 mol of AgCl.
Then 0.02495 moles of NaCl will give:
 of AgCl
 of AgCl
Mass of 0.02495 moles of AgCl:

The mass of the precipitate  that AgCl is 3.5803 g.
 
        
             
        
        
        
D. metamorphic rock melts and crystallizes to become igneous rock <span />
        
                    
             
        
        
        
River Banks? I'm not completely sure but hope this helps!
        
                    
             
        
        
        
The Law of Conservation of Mass<span> states that </span>matter <span>can neither be created nor destroyed in a chemical reaction.</span>