Question

What is the frequency of yellow

Answer 1

Answer:

5.131 × 10¹⁴  Hz

Step-by-step explanation:

Planck relation

$\large\boxed{E = hf}$

where:

• E = Energy of the photon (J).
• h = Planck's constant (J · s).
• f = frequency of light produced (Hz).

Given values:

• E = 3.4 × 10⁻¹⁹ J
• h = 6.626 × 10⁻³⁴ J · s

Substitute the given values into the formula and solve for f:

$\implies 3.4 \times 10^{-19}=(6.626 \times 10^{-34})f$

$\implies f=\dfrac{3.4 \times 10^{-19}}{6.626 \times 10^{-34}}$

$\implies f=\dfrac{3.4}{6.626} \times \dfrac{10^{-19}}{10^{-34}}$

$\implies f=0.5131\times 10^{(-19-(-34))}$

$\implies f=0.5131 \times 10^{15}$

$\implies f=5.131 \times 10^{14}$