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lesya [120]
3 years ago
14

The hypotenuse of a right triangle is 10 ft long. the shorter leg is 2ft shorter than the longer leg. find the side lengths of t

he triangle
Mathematics
1 answer:
Gwar [14]3 years ago
5 0
Since we have two possible pieces of information and 2 items to solve for, we know this is a system of equations.
Our first piece of information is that our shorter leg (s) is 2 feet shorter than our longer leg (l). This can be written as s=l-2.
Our second piece of information is that using the Pythagorean theorem that our shorter leg squared plus our longer leg squared is equal to our hypotenuse squared. This can be represented by s^2+l^2=10^2. Now we can solve.
We have already isolated for s in our first equation, so we can substitute l-2 in.
(l-2)^2+l^2=10^2
l-2+l=10
2l-2=10
2l=12
l=6
Now we can substitute in for s in our simpler equation
s=6-2
s=4
We now know that using our knowledge of systems of equations, the side lengths of this right angle triangle are 6 and 4.
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Find the greatest number which divides 6168, 2447 and 3118 leaving the same remainder in each case.
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let the greatest number be a and remainder be x. And let the whole number result of the division be b, c and d. So we have

ab + x = 2447............(1)

ac + x = 3118...............(2)

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