A pair of shoes is on sale for 15% off. With this discount, customers will save $9 if they buy the shoes. Part AIn this situatio
n, what is the PART, WHOLE, and PERCENT?15% is the ___, $9 is the _____ and the original price is the _____.Part BWhat was the original price of the shoes?$
1 answer:
Answer:
(b)The original price of the shoes is $60.
Explanation:
Part A
In this situation:
• 15% is the PERCENT
,• $9 is the PART
,• The original price is the WHOLE.
Part B
If 15% is taken off, the customer will save $9.
This means that 15% of the original price = $9.
Let the original price=p
The original price of the shoes is $60.
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Given the mean = 205 cm and standard deviation as 7.8cm
a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.
b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15) from 1. Therefore, we have 1- P(Z). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.
c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.
Step-by-step explanation:
Given the mean = 205 cm and standard deviation as 7.8cm
a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.
b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15) from 1. Therefore, we have 1- P(Z). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.
c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.
Answer:
or 1.945%
Step-by-step explanation:
Term annual percentage rate(APR) is the annual interest rate charged ona financial year for a duration of one year. APR can be converted to weekly, monthly, daily or even semi-annual rates using the below formula.
Effective rate for period = (1 + annual rate)(1 / n of periods) – 1
Rate is given as:
Answer:
Step-by-step explanation:
One is given the following equation;
The problem asks one to find the roots of the equation. The roots of a quadratic equation are the (x-coordinate) of the points where the graph of the equation intersects the x-axis. In essence, the zeros of the equation, these values can be found using the quadratic formula. In order to do this, one has to ensure that one side of the equation is solved for (0) and in standard form. This can be done with inverse operations;
This equation is now in standard form. The standard form of a quadratic equation complies with the following format;
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Substitute the coefficients of the given equation in and solve for the roots;
Simplify,
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