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AlladinOne [14]
1 year ago
5

A pair of shoes is on sale for 15% off. With this discount, customers will save $9 if they buy the shoes. Part AIn this situatio

n, what is the PART, WHOLE, and PERCENT?15% is the ___, $9 is the _____ and the original price is the _____.Part BWhat was the original price of the shoes?$

Mathematics
1 answer:
In-s [12.5K]1 year ago
8 0

Answer:

(b)The original price of the shoes is $60.

Explanation:

Part A

In this situation:

• 15% is the PERCENT

,

• $9 is the PART

,

• The original price is the WHOLE.

Part B

If 15% is taken off, the customer will save $9.

This means that 15% of the original price = $9.

Let the original price=p

\begin{gathered} 15\%\text{ of p=9} \\ \frac{15}{100}p=9 \\ 15p=900 \\ p=\frac{900}{15} \\ p=60 \end{gathered}

The original price of the shoes is $60.

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Option E

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(22.12, 27.48)

Step-by-step explanation:

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i.e. 24.8\pm(2.365)\dfrac{3.2}{\sqrt{8}}

24.8\pm2.67569206001\\\\\approx24.8\pm2.68\\\\=(24.8-2.68, 24.8+2.68)=(22.12, 27.48)

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How many Solutions does this system have? (1 point)
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The given system of equation that is 2x+y=3 and 6x=9-3y has infinite number of solutions.

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<u>Solution:</u>

Need to determine number of solution given system of equation has.

\begin{array}{l}{2 x+y=3} \\\\ {6 x=9-3 y}\end{array}

Let us first bring the equation in standard form for comparison

\begin{array}{l}{2 x+y-3=0} \\\\ {6 x+3 y-9=0}\end{array}

\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}

To check how many solutions are there for system of equations a_{1} x+b_{1} y+c_{1}=0 \text{ and }a_{2} x+b_{2} y+c_{2}=0, we need to compare ratios of \frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}} \text { and } \frac{c_{1}}{c_{2}}

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\begin{array}{l}{\Rightarrow \frac{a_{1}}{a_{2}}=\frac{2}{6}=\frac{1}{3}} \\\\ {\Rightarrow \frac{b_{1}}{b_{2}}=\frac{1}{3}} \\\\ {\Rightarrow \frac{c_{1}}{c_{2}}=\frac{-3}{-9}=\frac{1}{3}} \\\\ {\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}=\frac{1}{3}}\end{array}

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Hence, we can conclude that system has infinite number of solutions.

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