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Nadusha1986 [10]
3 years ago
6

Find the GCF of 24 and 108.

Mathematics
2 answers:
Veronika [31]3 years ago
6 0

Answer:

The GCF Is 12

Step-by-step explanation:

12 can go into 24 2 times, and 12 can go into 108 9 times.

Give brainliest.

AURORKA [14]3 years ago
6 0

Answer:

Step-by-step explanation:

24=6*4

2*2*2*3

108=2*2*3*3*3

gcf=12

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8+w/4 when w is 16<br> plz answer it for me plzzz
Marat540 [252]

Answer:

  1. 8+w/4
  2. Putting w = 16
  3. 8+16/4
  4. (32+16)/4
  5. = 48/4
  6. = 12

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

6 0
2 years ago
State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should
Yuki888 [10]

Solving for <em>Angles</em>

\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A

* Do not forget to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

Solving for <em>Edges</em>

\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2

You would use this law under <em>two</em> conditions:

  • One angle and two edges defined, while trying to solve for the <em>third edge</em>
  • ALL three edges defined

* Just make sure to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under <em>three</em> conditions:

  • Two angles and one edge defined, while trying to solve for the <em>second edge</em>
  • One angle and two edges defined, while trying to solve for the <em>second angle</em>
  • ALL three angles defined [<em>of which does not occur very often, but it all refers back to the first bullet</em>]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0
2 years ago
If two cards are drawn from a regular shuffled deck, what is the probability that both cards will be diamonds?​
Nastasia [14]

Answer: The first card is a diamond and the second card is a heart. Both cards are hearts. Let H denote the event that a heart is drawn; let D denote the event that a diamond is drawn. The first card is a diamond and the second card is a heart: The probability of drawing a diamond on the first draw

Step-by-step explanation:

6 0
2 years ago
Two secant segments intersect outside a circle as shown. What is the value of x?
torisob [31]
Using the intersecting secants theorem, QS*QR=QP*QM
3*13=2*(x+2)
39=2x+4
2x=35
x=17.5
8 0
3 years ago
Tom and Jane left for school, Tom walked to school on route A which was 4.5 kilometers while Jane walked to school on route B wh
Aleonysh [2.5K]

Answer:

3.95 km

Step-by-step explanation:

The computation is shown below:

As both left for school

Tom walked to school on route A i.e. 4.50 kilometer

And, Jane walked to school on route B i..e 8 kilometers & 450 meters i.e. 8.45 kilometers

So, the more km that jane would take to reach to school as compared with Tom is

= 8.45 km - 4.50 km

= 3.95 km

4 0
3 years ago
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