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Nadusha1986 [10]
3 years ago
6

Find the GCF of 24 and 108.

Mathematics
2 answers:
Veronika [31]3 years ago
6 0

Answer:

The GCF Is 12

Step-by-step explanation:

12 can go into 24 2 times, and 12 can go into 108 9 times.

Give brainliest.

AURORKA [14]3 years ago
6 0

Answer:

Step-by-step explanation:

24=6*4

2*2*2*3

108=2*2*3*3*3

gcf=12

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Zia has a slab of concrete in the shape of a parallelogram.
Aleksandr [31]

Answer:

270 in²

Step-by-step explanation:

The area of a parallelogram is given by the formula A = bh.

The base of the parallelogram is 9+9 = 18 inches.

The height of the parallelogram is 15 inches.

This makes the area 15(18) = 270 in²

7 0
3 years ago
Read 2 more answers
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
4 years ago
Complete the recursive formula of the geometric sequence 16\,,\,3.2\,,\,0.64\,,\,0.128,...16,3.2,0.64,0.128,
Nastasia [14]

Answer:

a_{n+1}=0.2a_n for all n>0, a_1=16

Step-by-step explanation:

Let \{a_n\}=\{16,3.2,0.64,0.128,\cdots \} be the sequence described.

A geometric sequence has the following property: there exists some r (the ratio of the sequence) such that \frac{a_{n+1}}{a_n}=r forr all n>0.

To find r, note that

\frac{3.2}{16}=\frac{32}{10(16)}=\frac{2}{10}=\frac{1}{5}=0.2

Similarly

\frac{0.64}{3.2}=\frac{64}{10(32)}=\frac{1}{5}=0.2

\frac{0.128}{0.64}=\frac{1}{5}=0.2

Thus a_{n+1}=r a_n=\frac{a_n}{5}=0.2a_n for all n>0, and a_1=16

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3 years ago
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Answer:

The screenshot is not included!!

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3 years ago
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KE=0.5xmxv2
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