Here's the general formula for bacteria growth/decay problems
Af = Ai (e^kt)
where:
Af = Final amount
Ai = Initial amount
k = growth rate constant
<span>t = time
But there's another formula for a doubling problem.
</span>kt = ln(2)
So, Colby (1)
k1A = ln(2) / t
k1A = ln(2) / 2 = 0.34657 per hour.
So, Jaquan (2)
k2A = ln(2) / t
<span>k2A = ln(2) /3 = 0.23105 per hour.
</span>
We need to use the rate of Colby and Jaquan in order to get the final amount in 1 day or 24 hours.
Af1 = 50(e^0.34657(24))
Af1 = 204,800
Af2 = 204,800 = Ai2(e^0.23105(24))
<span>Af2 = 800</span>
?? Pretty odd answers. An order of magnitude is defined as powers of 10: 0, 3, 20, 100, ... but not 0,1,2,3.
Then, I suppose 2, but that's all quite arbitrary. One would need some data.
Answer:1/15 or 0.06
Step-by-step explanation:
Divide 1/5 by 3 since there are 3 people sharing the bar.
Ok so this is what my friends told me. The mean mean the average, median means middle, mode means the value that occurs often and range is the difference between the largest and smallest values. i hope this helps any
Answer:
D) 5.2
Step-by-step explanation:
1/2 x (4.5 + 5.9) = 5.2