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Zepler [3.9K]
1 year ago
12

your sales operations group would like to perform monthly analyses on large amounts of sales activity. they want to be able to r

ank the performance of different territories, product categories, and sales channels. they will use visualization tools to generate graphical representations of the data. which aws service will provide the best solution for storing the sales data?
Computers and Technology
1 answer:
motikmotik1 year ago
6 0

The AWS service that will provide the best solution for storing the sales data is CloudFront.

A content delivery network (CDN) called Amazon CloudFront is run by Amazon Web Services (AWS). In order to improve access speed for downloading the material, content delivery networks offer a globally dispersed network of proxy servers that cache content, like web videos or other large media, more locally for customers.

Europe (the United Kingdom, Ireland, The Netherlands, Germany, Spain), Asia (Hong Kong, Singapore, Japan, Taiwan, and India), Australia, South America, Africa, and a number of significant US cities all have servers for CloudFront. The program ran from 400 edge locations across six continents in November 2022. CloudFront is a pay-as-you-go service.

Competitors of CloudFront include Limelight Networks and Akamai, two larger CDNs. When CloudFront first launched, Larry Dignan of ZDNet News warned that it might increase costs.

To know more about CloudFront click here:

brainly.com/question/14987275

#SPJ4

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Hope this helps!

4 0
3 years ago
Write a program that will open the file random.txt and calculate and display the following: A. The number of numbers in the file
Rama09 [41]

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

#include <fstream>  //to manipulate files

using namespace std;  //to identify objects like cin cout

int main(){  //start of main function

  ifstream file;   //creates an object of ifstream

   file.open("random.txt"); //open method to open random.txt file using object file of ifstream

       

    int numCount = 0;  //to store the number of all numbers in the file          

    double sum = 0;   //to store the sum of all numbers in the file

    double average = 0.0;   //to store the average of all numbers in the file

    int number ; //stores numbers in a file

                 

        if(!file){   //if file could not be opened

           cout<<"Error opening file!\n";    }   //displays this error message

       

       while(file>>number){   //reads each number from the file till the end of the file and stores into number variable

           numCount++; //adds 1 to the count of numCount each time a number is read from the file          

           sum += number;  }  //adds all the numbers and stores the result in sum variable

           average = sum/numCount;  //divides the computed sum of all numbers by the number of numbers in the file

     

       cout<<"The number of numbers in the file: "<<numCount<<endl;  //displays the number of numbers

       cout<<"The sum of all the numbers in the file: "<<sum<<endl;  //displays the sum of all numbers

       cout<<"The average of all the numbers in the file: "<< average<<endl;  //displays the average of all numbers

       file.close();     }  //closes the file    

   

Explanation:

Since the random.txt is not given to check the working of the above program, random.txt is created and some numbers are added to it:

35

48

21

56

74

93

88

109

150

16

while(file>>number) statement reads each number and stores it into number variable.

At first iteration:

35 is read and stored to number

numCount++;  becomes

numCount = numCount + 1

numCount = 1      

sum += number; this becomes:

sum = sum + number

sum = 0 + 35

sum = 35

At second iteration:

48 is read and stored to number

numCount++;  becomes

numCount = 1+ 1

numCount = 2    

sum += number; this becomes:

sum = sum + number

sum = 35 + 48

sum = 83

So at each iteration a number is read from file, the numCount increments to 1 at each iteration and the number is added to the sum.

At last iteration:

16 is read and stored to number

numCount++;  becomes

numCount = 9 + 1

numCount = 10    

sum += number; this becomes:

sum = sum + number

sum = 674 + 16

sum = 690

Now the loop breaks and the program moves to the statement:

       average = sum/numCount;  this becomes:

       average = 690/10;

       average = 69

So the entire output of the program is:

The number of numbers in the file: 10                                                                                                           The sum of all the numbers in the file: 690                                                                                                     The average of all the numbers in the file: 69

The screenshot of the program and its output is attached.

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Answer:

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